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ludmilkaskok [199]
3 years ago
9

The area of a rectangle is 100 in.² the perimeter of the rectangle is 40 inches. A second rectangle has the same area but a diff

erent perimeter. Is the second rectangle or square?
Mathematics
1 answer:
poizon [28]3 years ago
5 0
Square. a square can be a rectangle but a rectangle cannot be a square.
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im pretty sure B 7.5 units

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20%

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A line m is perpendicular to an angle bisector of ∠A. The sides of ∠A intersect this line m at points M and N. Prove that △AMN i
Ray Of Light [21]

Answer:


Step-by-step explanation:

<em><u>Given</u></em><u>:</u>       A line m is perpendicular to the angle bisector of ∠A. We call this  

                 intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

                 AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.

<u><em>To Prove</em></u>:   <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>

<em>                    </em><em><u>equal. </u></em>

<em><u>Solution</u></em>:  Now, In ΔADM and ΔADN

                 ∠MAD=∠NAD     ...(1) (∵Given)

                  AD=AD                ...(2) (∵common side)

                  ∠ADM=∠ADN     ...(3) (∵Given)

                  <u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>

                                                         ( ∵ ASA  congruence rule)

                  ⇒<u><em> AM=AN</em></u>

                  Now, In Δ AMN

                 AM=AN (∵ Proved)

                  Hence, ΔAMN is an isosceles  triangle.


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3 years ago
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ohaa [14]

Answer:

B

Step-by-step explanation:

The line is solid, so eliminate A and D.

Also, the line is shaded below, so this eliminates C.

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