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Papessa [141]
3 years ago
14

Square root of 45 minus square root of 5

Mathematics
2 answers:
NikAS [45]3 years ago
8 0

Answer:

4.472135955

Step-by-step explanation:

Morgarella [4.7K]3 years ago
7 0

Answer:

i think it's 1.7082039325

Step-by-step explanation:

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You rented a bike to ride on the beach. The one-time fee was $12 and you were charged S5 per hour. It cost you a total of $27 to
e-lub [12.9K]

Answer:

5 hours and 2 minutes?

Step-by-step explanation:

5,10,15,20,25 + the two=27

5 0
2 years ago
Read 2 more answers
What value for x makes the equation true?
fgiga [73]

Since we already have 3^7 you should know that 3 times 3 is 9. Here is how I would simplify it.

3^7 times 3^4 times 3^3

You should add all the exponents and get

3^14

27 is basically 3 times 3 times 3 which is why I chose to put 27 that way

8 0
3 years ago
Select the correct answer.
larisa [96]

Answer:

B

Step-by-step explanation:

In this graph we can see a "Parabola", this is the curve for a second degree polynomial function, and based on "Fundamental theorem of algebra" we can know that this polynomial has 2 roots (they can be real or imaginary).

In this graph, the curve doesn't touch the X axis, so we know that this function has not real root. So both roots are complex

8 0
3 years ago
Save me the headache
maxonik [38]

(9\sin2x+9\cos2x)^2=81

Taking the square root of both sides gives two possible cases,

9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1

or

9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1

Recall that

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

If \alpha=2x and \beta=\dfrac\pi4, we have

\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}

so in the equations above, we can write

\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1

Then in the first case,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi

(where n is any integer)

\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi

\implies x=n\pi\text{ or }\dfrac\pi4+n\pi

and in the second,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi

\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi

\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi

Then the solutions that fall in the interval [0,2\pi) are

x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4

5 0
3 years ago
Read 2 more answers
A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function
Aloiza [94]

The ball's maximum height is 30.25 feet.

<h3>What is quadratic equation?</h3>

A quadratic equation in math is a second-degree equation of the form ax² + bx + c = 0. Here a, b, are the coefficients, c is the constant term, and x is the variable.

Given:

h= -16t²+36t+10

Differentiate w.r.t. 't',

h' = -32t+36

When h=0, that will be the maximum height

32t= 36

t= 9/8

t= 1.125 sec.

So, The maximum height is

h(1.123)= -16(1.125)² + 36*1.125+10

h(1.125) = 30.25 feet.

Learn more about this concept here:

brainly.com/question/10335037

#SPJ1

5 0
1 year ago
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