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3 years ago

14

Square root of 45 minus square root of 5

2 answers:

NikAS [45]3 years ago

8 0

Answer:

4.472135955

Step-by-step explanation:

Morgarella [4.7K]3 years ago

7 0

Answer:

i think it's 1.7082039325

Step-by-step explanation:

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Could anyone help me decipher this alien language????

Shkiper50 [21]

Answer:

OPTION A: $\frac{11}{20}$

Step-by-step explanation:

$P(A | B) = \frac{P(A \cap B)}{P(B)}$

$P(not B) = 1 - P(B) = 1 - \frac{13}{20} = \frac{7}{20}$

$\implies P(A \cap B)= P(A | B) \times P(B)$

$= \frac{11}{20} \times \frac{7}{20}$

Let us keep it without multiplying for easy simplification later.

Also, let us assume A and B are independent events.

$P(A \cap B) = P(A) \times P(B)$

$\implies \frac{11}{20} \times \frac{7}{20} = P(A) \times \frac{7}{20}$

$\implies P(A) = \frac{11}{20}$

Hence, OPTION A 11/20 is the answer.

3 0

3 years ago

The markings of a standard ruler

IgorC [24]

12 inches and 31 cm.

6 0

3 years ago

Find the other endpoint of the line segment with the given endpoint and midpoint. Round to the

dsp73

The answer is (-15,8), hope this helps- if you can mark brainliest that’d be awesome thanks

6 0

3 years ago

An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in Texas. He believes that

Llana [10]

Answer:

We need a sample size of at least 170.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.8}{2} = 0.1$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.1 = 0.9$ , so $z = 1.28$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population(square root of the variance) and n is the size of the sample.

How large of a sample would be required in order to estimate the mean per capita income at the 80%80% level of confidence with an error of at most $0.52$ 0.52?

A sample size of at least n, in which n is found when $M = 0.52, \sigma = \sqrt{34.81} = 5.9$

So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.58 = 1.28*\frac{5.9}{\sqrt{n}}$

$0.58\sqrt{n} = 1.28*5.9$

$\sqrt{n} = \frac{1.28*5.9}{0.58}$

$(\sqrt{n})^{2} = (\frac{1.28*5.9}{0.58})^{2}$

$n = 169.5$

Rounding up

We need a sample size of at least 170.

6 0

3 years ago

Help me out yall PLEASE

Alenkinab [10]

Answer: QRU and QRP

hope this helps :D

6 0

2 years ago