Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
The domain of a step function is all real numbers.
14+5(x+3)-7
14+(5x+15)-7
7+5x+15
5x+22
Answer:
Step-by-step explanation:
as given j=h and k=m then which expression for g is
as from attached image , we can see that its look like two right angle triangle
so from lower triangle we apply the pythagorean theorem .
which state that sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse.
so small triangle ΔEBD
h² +k²= g² ---------------(1)
now from big triangle ΔABC
(j + h)² +(m + h)² =f²---------(2)
given j=h and k=m so from equation-2 we can find ,
(h + h)² +(k+ k)² =f²
(2h)² +(2k)²=f²
4h²+ 4k²= f²
4(h²+k²)= f² ----------(3)
now from equation 1 and 3 we can obtained .
4×g² =f²
take square root both side we get,
2×g=f
so g=f/2----- Answer
The following is the rest of the question:
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Mikey's results showed that although both mice gained weight over the
month, mouse 2 gained more weight than mouse 1.Which graph below best
shows these results?
The complete figure is attached
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Solution:
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Graph (1)⇒⇒⇒ mouse 2 has constant weight and mouse 1 gained weight
Graph (3)⇒⇒⇒ mouse 2 has did not gain weight and mouse 1 gained weight
∴ Graph (1) and (3) are incorrect because both mice gained weight .
Graph (4) is incorrect because mouse 2 gained more weight than mouse 1
So, the correct answer is graph (2)