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ch4aika [34]
3 years ago
7

Of the 126 seniors at Kirby Prep School, 35 are taking art classes, 54 are taking computer classes, and 7 are taking both. How m

any students are taking neither course?
Mathematics
1 answer:
hoa [83]3 years ago
6 0

Answer:23

Step-by-step explanation:

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Find the diameter of the object.
Anni [7]

Answer:

1 \frac{1}{5} centimeters

Step-by-step explanation:

The diameter is equal to the radius × 2. We know that the radius is equal to 3/5 centimeters.

To solve this you must do \frac{3}{5} × 2.

This equals \frac{6}{5}, or 1 \frac{1}{5} cm.

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3 years ago
What is the value of x to the nearest tenth?
Citrus2011 [14]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
Please help and show your work it’s due today
anygoal [31]
X = 15
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5 0
3 years ago
Consider the radical equation √c+22 = c + 2.
dimulka [17.4K]

First square both sides to get:

c + 22 = (c + 2)^2

or

c + 22 = c^2 + 4c + 4

Move the terms on the left side to the right side:

c^2 + 3c - 18 = 0

Factor to get:

(c + 6) * (c - 3) = 0.

The solutions are c = -6 and c = 3.

Check to see if these answers work by plugging them into the original equation:

c = -6:

sqrt (-6 + 22) ?= -6 + 2

But, -6 + 2 is a negative number, and you can't get a negative from a square root. So, -6 is extraneous.

c = 3:

sqrt (3 + 22) ?= 3 + 2

5 = 5. So, 3 works.

The answer is: B

7 0
3 years ago
How would you find the quadratic that goes through the point (4,0), the axis of symmetry is x=7, and it also goes through the po
nasty-shy [4]

9514 1404 393

Answer:

  y = (5/27)(x -7)^2 -5/3

Step-by-step explanation:

Use the given points to find the unknowns in the equation.

If the axis of symmetry is x=7, then the equation can be written in the form ...

  y = a(x -7)^2 +b

Filling in the two point values, we have two equations:

  0 = a(4 -7)^2 +b   ⇒   9a +b = 0

  5 = a(1 -7)^2 +b   ⇒   36a +b = 5

__

Subtracting the first equation from the second, we have ...

  (36a +b) -(9a +b) = (5) -(0)

  27a = 5

  a = 5/27

Substituting that value into the first equation gives ...

  9(5/27) +b = 0

  5/3 +b = 0

  b = -5/3

So, the quadratic can be written in vertex form as ...

  y = (5/27)(x -7)^2 -5/3

4 0
3 years ago
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