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bonufazy [111]
3 years ago
6

PLS Help!!! I am super confused

Mathematics
2 answers:
sdas [7]3 years ago
7 0

Answer:

I would say you are correct with your answer

Step-by-step explanation:

hope it is correct

UNO [17]3 years ago
5 0

Answer:

84

Step-by-step explanation:

Use the pythagorean theorem to solve the equation.

Line it up like this:

A=12 B=14 C=?

a^2 + b^2 = c^2

12^2 + 14^2 = c^2

144 + 196 = c^2

\sqrt\\144 + 196 = \sqrt c^{2}

2\sqrt{85} = c

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Determine algebraically the zeros of f(x)=3x^3+21x^2+36x
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Answer:

The zeros of the given polynomial function f(x) are -3,0,-4

Step-by-step explanation:

Given polynomial is f(x)=3x^3+21x^2+36x

To find the zeros of the given polynomial:

First equate the polynomial function f(x) to zero

That is f(x)=3x^3+21x^2+36x=0

By synthetic division we can solve it

-3_| 3      21       36     0

      0       -9      -36    0

   _____________________

      3      12        0        0

      Therefore x+3 is a factor

    That is x=-3 is a zero

    3x^2+12x=0

    3x(x+4)=0

    3x=0 or x+4=0

    Therefore x=0 or x=-4

    Therefore the zeros are -3,0,-4

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What's the absolute value of |10-34|
My name is Ann [436]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • |Absolute Value| - makes any negative number positive

Step-by-step explanation:

<u>Step 1: Define</u>

|10 - 34|

<u>Step 2: Evaluate</u>

  1. Subtract:                    |-24|
  2. |Absolute|:                  24
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