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Sav [38]
3 years ago
13

Rae earns $60 for playing music on saturday nights at the local coffee house. she makes an average of $5.25 in tips per hour. wr

ite the function of rae's earnings, and solve for how much she would make after 4 hours. y = 5.25x + 60; $65.25 y = 60x + 5.25; $85.75 y = 5.25x + 60; $81.00 y = 60x + 5.25; $185.25
Mathematics
1 answer:
insens350 [35]3 years ago
6 0
Okay. So for this equation, she would make $60, plus $5.25 in tips each hour. So for this, she would get $60 + 5.25h. Plug in 4 hours, and she would make $21 off of tips, plus the $60, which brings her up to $81 total. The answer is C.
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Answer:It's 18

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In 2002, Tiger Woods won the masters tournament. His scores were -4, -3, -2, and -1. What was his final score?
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An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
masya89 [10]

Answer:

P(X\leq 1) = 0.331

Step-by-step explanation:

Given

Poisson Distribution;

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Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
2 years ago
Da<br> A<br> Solve the equation 2x^2+3=0
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

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<u>Algebra I</u>

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<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

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<u>Step 2: Solve for </u><em><u>x</u></em>

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