Answer: 60
Step-by-step explanation:
You have to use Pythagorean Theorem because the other side is not listed of the triangle
Pythagorean Theorem: a² + b² = c²
a² + 20² = 25²
a² + 400 = 625
625-400 = a²
a² = 225
Find the square root of 225 to find the missing length
= 15 (this is the missing length for QS
To find the perimeter, add all the sides...
15 + 20 +25 = 60
Answer:
<em>y-9=0(x-6)</em>
<em>Or, equivalently: y=9</em>
<em>This represents a horizontal line</em>
Step-by-step explanation:
<em>Equation of the line</em>
The point-slope form of the equation of a line is:

Where m is the slope and (h,k) is a point through which the line passes.
Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

The points are (6,9) and (7,9). These points dfine a horizontal line, as we'll see later.
The slope is:

m=0
Now compute the equation in point-slope form:
y-9=0(x-6)
Solving for y:
y=9
This represents a horizontal line
Answer:
x = 7.7
Option B
Step-by-step explanation:

∴ value of x is 7.7
Answer:it the 3rd one
Step-by-step explanation:
I done this
Answer:
the answer is d. 4x²+x-6
Step-by-step explanation:
In order to combine the fractions, they need to have the same denominator.
So, multiply each of their numerators by the denominator they need to be equivalent.
This would look like this:
3x/x+3 --> 3x(x)/x(x+3) ---simplify this as--> 3x²/x(x+3)
x-2/x --> (x-2)(x+3)/x(x+3) ---simplify this as --> x²+x - 6/x(x+3)
3x 3x(x) x-2 (x-2)(x+3)
----- ---> ----- and -------- ---> ---------
x+3 x(x+3) x x(x+3)
now that both fractions have the same denominator, we can add their numerators.
3x² + x²+x-6 = 4x²+x -6
This should now look like this:
4x²+x -6
-------------
x(x+3)