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HACTEHA [7]
3 years ago
11

Help please! show work thanks

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0
Answers
b = 2.77 m
A = 43.0°
C = 111.1°

cosine law to find b

b^2 = a^2 + c^2 -2ac \cos B \\ \\
b = \sqrt{a^2 + c^2 -2ac \cos B} \\ \\
b = \sqrt{4.33^2 + 5.92^2 - 2(4.33)(5.92) \cos 25.9} \\
b = 2.7708\ m

b = 2.7708\ m

Find angle A with sine law

\displaystyle
\frac{\sin A}{a} = \frac{\sin B}{b} \\ \\
\sin A = \frac{a \sin B}{b} \\ \\
A = \sin^{-1} \left[ \frac{a \sin B}{b}  \right] \\ \\
A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708}  \right]  \\ \\
A = 43.0467020

Find C with angles in triangle sum to 180

A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
C = 111.1
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