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3 years ago

calculate the side lengths a and b to two decimal places angle a is 64 angle b is 85 and line ab is 9.3? PLEASE HELP ASAP

1 answer:

4 0

∠C = 180° - (∠A + ∠B) = 180° - (64° + 85°) = 180° - 149° = 31°
$AC= \frac{9.3*sin(85)}{sin(31)} = \frac{9.3*0.9962}{0.515} =17,99 \\ \\ BC=\frac{9.3*sin(64)}{sin(31)} = \frac{9.3*0.8988}{0.515} =16,2$

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Answer: $4$ pairs

Step-by-step explanation:

Given

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3 years ago

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Firdavs [7]

Answer:

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C) The most general solution is

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Step-by-step explanation:

Given non homogeneous ODE is

$y''+4y'+5y=10x+e^{-x}---(1)$

To find homogeneous solution:

$D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)$

To find particular solution:

$y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\$

Substituting $y_{p},y'_{p},y''_{p}$ in (1)

$y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\$

Equating the coefficients

$5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\$

The general solution is

$y=y_{h}+y_{p}$

from (2) ad (3)

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Attached the solution with work shown.

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