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Triangle DNO has vertices at D(5, 8), N(– 3, 10), and O(– 3, 6). If vertex D is translated 4 units to the right, the best name f

prisoha [69]

Using distance between two points to find the lengths of the edges of the triangle, the correct option is:

b. Isosceles

The distance between two points, $(x_1,y_1)$ and $(x_2,y_2)$ , is given by:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Vertex D is translated 4 units to the right is (9,8).

The lengths of the edges are:

$DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4$

Two edges of the same length, hence, it is an isosceles triangle, given by option b.

You can learn more about distance between two points at brainly.com/question/18345417

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