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3 years ago

PLLLZZZZZZZZZ HELLLLPPPPPPP

Mathematics

1 answer:

bulgar [2K]3 years ago

8 0

$w \leqslant 15$

$\frac{1}{3?} w \: - 2 + 2 \geqslant 3 + 2 \\ 3 \times \frac{1}{3} w \geqslant 5 \times 3 \\ w \geqslant 15$

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3 years ago

Please help solve with work

sergey [27]

X-4y=28
8x+4y=8
---------------
9x=36→x=4
4-4y=28→y=6
—-----------------------------------------------------------
y-5=x
4(y-5)-y=4
4y-20-y=4
3y=24
y=8
x8-5=3

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3 years ago

A.Two friends share 76 blueberries

Anna71 [15]

They would have to split apart the group with 6 blueberries. Each friend would get three blueberries from this group.

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3 years ago

Which equation is equivalent to 16 Superscript 2 p Baseline = 32 Superscript p 3?.

Mrac [35]

The equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

$2^{8p}=2^{5p+15}$

<h3>What is equivalent equation?</h3>

Equivalent equation are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The given equation in the problem is,

$16^{2p}=32^{p+3}$

Write both the equation in the form of same base number as,

$(2^4)^{2p}=(2^5)^{p+3}$

The power of the power of a number can be written as product of both the numbers. Thus,

$(2)^{4\times2p}=(2)^{5\times(p+3)}\\2^{8P}=2^{5P+15}$

This is the required equation.

Now if the base is the same at both side of the expression, then the powers can be compared. Thus,

$8p=5p+15$

Solve it further to find the value of p as,

$8p-5p=15\\3p=15\\p=5$

Thus the equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

$2^{8p}=2^{5p+15}$

Learn more about the equivalent expression here;

brainly.com/question/2972832

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2 years ago

PLEASE HELP ASAP!! Also, please explain how to solve. Thank you

DENIUS [597]

By evaluating the given relation, we conclude that the correct options are A, D, and G.

<h3>How to check if the points are on the graph?</h3>

We have the relation:

k = ∛(V/7)

Such that this relation gives us pairs of the form (V, k).

So, to check if the points belong to the graph of the relation, we need to evaluate the points on the given relation and see if the relation is true.

A) (0, 0) gives:

Evaluating in V = 0

k = ∛(0/7) = 0

So this point belongs.

B) (1, 1) gives:

k= ∛(1/7) = 0.52

So we have the point (1, 0.52) and the point (1, 1) then does not belong to the graph.

We just need to do that for all the points, evaluate V and see if k gives the same value as in the point.

With this method, we will see that the correct options are:

D) (7, 1)

k= ∛(7/7) = 1

G) (56, 2)

k= ∛(56/7) = ∛(8) = 2

If you want to learn more about evaluations, you can read:

brainly.com/question/4344214

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3 years ago