Answer:
The oxidation number of strontium is +2.
Explanation:
Answer:
10
Explanation:
Binary search's runtime is proportional to log (base two) of the number of list elements.
<h3>
Answer:</h3>
43.5 mL
<h3>
Explanation:</h3>
We are given;
- Molarity of dilute acetic acid is 1.74 M
- Volume of the solution that needs to be prepared is 200 mL
- Molarity of the stock solution 8 M
We are required to determine the volume of acid that must be used.
- We need to know the dilution formula;
- According to the dilution equation;
M1V1 = M2V2
Rearranging the formula;
V1 = M2V2 ÷ M1
= (1.74 M × 200 mL) ÷ 8 M
= 43.5 mL
Therefore, the volume of the concentrated acid that must be added is 43.5 mL
I...what? What are you saying my boi
Answer:
38.9%
Explanation:
below, determine the mass percent of Fe3+ in a 0.6450 g sample of iron ore, if 22.40 mL of a 0.1000 M stannous chloride, SnCl2(aq), solution is required to completely react with the Fe3+ present in the ore sample. The chemical equation for the reaction is
2 Fe3+ (aq) + Sn2+ (aq) →2Fe2+ (aq) + Snº+(aq).
O 19.40%
O 6.196%
O 38.79%
O 9.697%
2 Fe3+ (aq) + Sn2+ (aq) →2Fe2+ (aq) + Snº+(aq).ole of Sn2+
for every mole of Sn2+, tere are 2 moles of Fe3+
- 22.4/1000L of 0.1000 M Sn2+ = 22.4 X 0.10/1000 = 0.00224 mole
so there are 0.00224 X 2= 0.00448 moles Fe3+
iron atomic mass is 56
56 X 0.00448 = 0.251 gm Fe3+
so the mass % of the Fe3+ in the 0.645 gm iron ore sample is
(0.251/0.645) X 100 = 38.9%
