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jok3333 [9.3K]
3 years ago
7

Select all of the answers that apply. Without its atmosphere, Earth would be _____. warmer bombarded by meteorites similar to Ma

rs relatively lifeless

Chemistry
2 answers:
kow [346]3 years ago
8 0

The answer is B, C and D

Papessa [141]3 years ago
6 0
Without its atmosphere, Earth would be bombarded by meteorites, similar to mars, relatively lifeless. Without the atmosphere objects can just enter the atmosphere and cause serious harm to us, but with the atmosphere it basically reduces damage and shrinks it to size. Without the atmosphere earth would be like mars since it doesn't have a atmosphere. Without the atmosphere earth would be relatively lifeless since without air, us humans cant breathe so we will not survive.

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During science lab, Carl notices that when he adds water to his solid sample of anhydrous copper
Bond [772]

Answer:

The dissociation of copper sulfate into ions is an exothermic chemical reaction that releases heat into the surroundings.

Explanation:

Some of the potential energy stored in the solid sample of anhydrous copper sulfate is released as heat as the sample dissolves and dissociates into ions in the water. This is due to the large lattice energy of the crystalline copper sulfate.

hope this helps

4 0
3 years ago
A volume of 80.0 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. I
murzikaleks [220]

Answer:

The mass of the steel bar is 26.833 grams

Explanation:

<u>Step 1: </u>data given

ΣQ gained = ΣQ lost

Q=m*C*ΔT

with m = mass in grams

with C= specific heat capacity ( in J/(g°C))

with ΔT = change in temperature = T2-T1

Qsteel = Qwater

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

Mass of steel = TO BE  DETERMINED

mass of water =⇒ since 1mL = 1g : 80 mL = 80g

Csteel =0.452 J/(g °C

Cwater = 4.18 J/(g °C

initial temperature steel T1 : 2 °C

final temperature steel T2 = 21.3 °C

initial temperature water T1 =22 °C

final temperature water T2 = 21.3 °C

<u>Step 2:</u> Calculate mass of steel

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

msteel * 0.452 *(21.3-2) = 80 * 4.18 * (21.3-22)

msteel = (80 * 4.18 * (-0.7)) / (0.452 * 19.3)

msteel = -234.08 / 8.7236

msteel = -26.833 g

Since mass can't be negative we should take the absolute value of it = 26.833g

The mass of the steel bar is 26.833 grams

6 0
3 years ago
If 4520 kj of heat is needed to boil a sample of water, what is the mass of water
Cerrena [4.2K]

Answer:

1,085g of water

Explanation:

If we have the value 4520kj is because the question is related to Energy and heat capacity. In this case, the law and equation that we use is the following:

                                                  Q= m*C*Δt  where;

Q in the heat, in this case: 4520kj

m is the mas

Δt= is the difference between final-initial temperature (change of temperature), in this exercise we don´t have temperatura change.

In order to determine the mass, I will have the same equation but finding m

                                          m= Q/C*Δt    without   m=Q/C

So: m= 4,520J/4.18J/g°C

      m= 1,0813 g

5 0
3 years ago
Which subscripts would properly complete the formula unit Al_N_?
MakcuM [25]
I believe that it would be Al1N1.
4 0
3 years ago
Question 12 A chemistry student must write down in her lab notebook the concentration of a solution of sodium thiosulfate. The c
o-na [289]

Weight of sodium thiosulfate   = 76.148 - 8.2

= 67.948 g.

Concentration of the solution = 67.948 / 172.7

= 0.393 g / mL.  to the nearest thousandth . (answer).

3 0
3 years ago
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