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2 years ago

What is the median of the data set?

1 answer:

6 0

7. because you would put the number set into order from least to greatest first, ti would look like this: 2,3,4,5,9,10,12,12. then go to the middle, crossing one from each side off at one time. Then you get 5 and 9 in the middle. Then the middle between 5 and 9 is seven, you can check this by: 5+9=14, then 14/2= 7.
Your median is 7.

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If a projectile is fired straight upward from the ground with an initial speed of 64 feet per

natali 33 [55]

Answer:

h = 64 feet

Step-by-step explanation:

If you graph the function you see that 64 feet is the maximum of the parabola so this is the max height that the projectile reaches.

3 0

2 years ago

Mathematical Statement Justification

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

1. Given mathematical statement

$4x+3=x+5-2x$

So,

$\begin{array}{cc}4x+3=x+5-2x&\text{ Given}\end{array}$

2. Rewrite it as

$4x+3=x-2x+5$

So,

$\begin{array}{cc}4x+3=x-2x+5&\text{ Commutative property of addition}\end{array}$

3. Combine like terms $x$ and $-2x:$

$4x+3=-x+5$

So,

$\begin{array}{cc}4x+3=-x+5&\text{ Combine like terms}\end{array}$

4. Add $x$ to both sides:

$4x+3+x=-x+5+x\\ \\5x+3=5$

So,

$\begin{array}{cc}5x+3=5&\text{ Addition property of equality}\end{array}$

5. Subtract 3 from both sides:

$5x+3-3=5-3\\ \\5x=2$

So,

$\begin{array}{cc}5x=2&\text{ Subtraction property of equality}\end{array}$

6. Divide both sides by 5:

$x=\dfrac{2}{5}$

So,

$\begin{array}{cc}x=\dfrac{2}{5}&\text{ Division property of equality}\end{array}$

6 0

2 years ago

Read 2 more answers

Please help, see attatched file.

liubo4ka [24]

The answer above is correct.

4 0

3 years ago

Can someone please solve for x

yaroslaw [1]

Answer:

x=-12

Step-by-step explanation:

AC=AB+BC

x+29=2x+33+8

x-2x=33+8-29

-x=12

x=-12

7 0

2 years ago

Read 2 more answers

Find the differential of each function. (a) y = tan( 7t ) dy = Incorrect: Your answer is incorrect. (b) y = 4 − v2 4 + v2 dy =

Kisachek [45]

Answer:

$(a) dy= 7sec^2(7t)dt\\\\(b) dy = \frac{-16v}{(4+v^2)^2} dv$

Step-by-step explanation:

Given;

(a) y = tan (7t)

let u = 7t

y = tan(u)

du/dt = 7

dy/du = sec²(u)

$\frac{dy}{dt} = \frac{dy}{du} *\frac{du}{dt}\\\\\frac{dy}{dt} = sec^2(u)* 7\\\\\frac{dy}{dt} =7sec^2(u)\\\\\frac{dy}{dt} = 7sec^2(7t)\\\\dy = 7sec^2(7t)dt$

(b)

$y = \frac{4-v^2}{4+v^2}\\\\$

let u = 4 - v²

du/dv = -2v

let v = 4 + v²

dv/du = 2v

$y = \frac{4-v^2}{4+v^2}\\\\\frac{dy}{dv} = \frac{vdu-udv}{v^2} \\\\\frac{dy}{dv} =\frac{-2v(4+v^2)-2v(4-v^2)}{(4+v^2)^2}\\\\\frac{dy}{dv} =\frac{-8v-2v^3-8v+2v^3}{(4+v^2)^2}\\\\\frac{dy}{dv} =\frac{-16v}{(4+v^2)^2}\\\\dy = \frac{-16v}{(4+v^2)^2}dv$

6 0

3 years ago