Question

A number cube with six sides numbered 1 through 6 is rolled. The probability of rolling a 5 is 16 . What is the probability of not rolling a 5? Enter your answer as a fraction, in simplest form, in the box.

Answer 1

The probability would be 84, or as a fraction would be 42/50.

Hope This Helps!

Answer 2

Answer: $\dfrac{5}{6}$

Step-by-step explanation:

For any event A , the probability of not getting A is given by :-

P(not A)= 1- P(A)

Given : A number cube with six sides numbered 1 through 6 is rolled.

Then we have,

The total number of possible outcomes = 6

Also, it is given that , The probability of rolling a 5 is

P(rolling 5)=$\dfrac{1}{6}$.

Now, the probability of not rolling a 5 will be :-

P(not rolling a 5)= 1- P(rolling 5)

$=1-\dfrac{1}{6}=\dfrac{6-1}{6}=\dfrac{5}{6}$.

Hence, the  probability of not rolling a 5 =$\dfrac{5}{6}$