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Hunter-Best [27]
3 years ago
9

What is the equation of the line expressed in slope-intercept form?

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0
(x,y)
x=how far to the right
y=how far up
ok so
y=mx+b
m=slope
b=y intercept or where the line intercept the y axis

it looks like the line intercept the y axis at 2 high so
y=mx+2
we look at our options and we see that there is only 1 equation that has y=mx+2
that is B
B is the answer
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I believe it should be 1.296 miles
4 0
3 years ago
Can someone pls help with these geometry questions, it’s urgent.
Phantasy [73]

Answer:

6. x + x + 14 = 90

   2x + 14 = 90

   2x = 76

   x = 38

angle b = 38 + 14 = 52°

7. angles on a straight line add up to 180°

   x + x - 32 = 180

   2x = 212

    x = 106°

angle d = 106 - 32 = 74°

8. vertically opposite angles are equal

   7x - 80 = 3x

    -80 = -4x

     20 = x

angle 1 = 7(20) - 80 = 60°

angle 2 = 3(20) = 60°

7 0
2 years ago
Pre-Calc: Find all the zeros of the function.
uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Read more about polynomial at

brainly.com/question/17517586

#SPJ1

5 0
1 year ago
(posting this for my friend) SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER
Pani-rosa [81]

Answer:

45

Step-by-step explanation:

the 90 degree angle is subtracted by 45 and the answer is.

4 0
3 years ago
Can anyone help me pleassseeee!
Xelga [282]

Answer:

baba booey

Step-by-step explanation:

3 0
3 years ago
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