Help graphs are not my favorite

1. Grace was given the equation 2x + 20 = 15. She decides to add 10 to both sides of the equation. a.) Is that an acceptable mov

vlada-n [284]

9514 1404 393

Answer:

yes
2x +30 = 25

Step-by-step explanation:

Adding the same number to both sides of the equation is an acceptable move. The addition property of equality tells Grace that the value of the variable will remain unchanged by such a move.

Her new equation would be ...

2x +20 +10 = 15 +10

2x +30 = 25 . . . . the result of Grace's move

_____

<em>Additional comment</em>

There may be very good reasons why Grace would want to do that. If solving the equation is Grace's intent, that move would be counterproductive. For the purpose of solving the equation, it would be more productive to either subtract 20 from both sides, or divide both sides by 2. These steps would give, respectively, ...

2x = -5

x +10 = 7.5

6 0

3 years ago

What is the range of the graph below?<br>

torisob [31]

Answer:

B) -4 < y

Step-by-step explanation:

The lowest point on the y axis of the graph is -4 and everything else is higher

6 0

3 years ago

How do you simplify 8+(9t+4)

IrinaVladis [17]

8+(9t+4)
remove ( )
since there's a + in front of the ( ) the value will not change

8+9t+4
combine like terms

9t+12
Hope this helps

3 0

3 years ago

How does the graph of f(x)=3lx+2l+4 relate to its parent function?

Sergeeva-Olga [200]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units

check the picture below

7 0

2 years ago

8. The Last Supper

Salsk061 [2.6K]

The number of possible seats is an illustration of permutation

There are 1728 possible sitting arrangements

<h3>How to determine the number of seats</h3>

From the question, we have the following highlights:

Chris can only take 1 seat (i.e. the central seat)
Jo can take 2 seats (i.e. the seats adjacent the central seat)
Alex, Barb and Dave can take 3! number of seats
Eddie, Fred, and Gareth can take 3! number of seats on the right of Chris.
The remaining 4 adults do not have preference, then they can seat in 4! ways

So, the number of sitting arrangement is:

$n = 1 * 2 * 3! * 3! * 4!$

Evaluate the product

$n = 1728$

Hence, there are 1728 possible sitting arrangements

Help graphs are not my favorite​

Help graphs are not my favorite