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drek231 [11]
3 years ago
11

Find the point, M, that divides segment AB into a ratio of 5:6 if A is at (0, 22) and B is at (11, 0). A) (5, 12) B) (5, 11) C)

(6, 12) D) (6, 11)
Mathematics
2 answers:
amid [387]3 years ago
6 0
\bf \left. \qquad  \right.\textit{internal division of a line segment}
\\\\\\
A(0,22)\qquad B(11,0)\qquad
\qquad 5:6\quad \textit{from A to B}
\\\\\\
\cfrac{AM}{MB} = \cfrac{5}{6}\implies \cfrac{A}{B} = \cfrac{5}{6}\implies 6A=5B\implies 6(0,22)=5(11,0)\\\\
-------------------------------\\\\

\bf { M=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\\
-------------------------------\\\\
M=\left(\cfrac{(6\cdot 0)+(5\cdot 11)}{5+6}\quad ,\quad \cfrac{(6\cdot 22)+(5\cdot 0)}{5+6}\right)
\\\\\\
M=\left( \cfrac{55}{11}~~,~~\cfrac{132}{11} \right)

and surely you know what that is.
lozanna [386]3 years ago
4 0

Answer:

Answer is (5,12) if anyone wanted to know

Step-by-step explanation:


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