Answer:
They can be seated in 120 differents ways.
Step-by-step explanation:
Taking into account that there are 3 couples and every couple has an specific way to sit, for simplify the exercise, every couple is going to act like 1 option and it's going to occupy 1 Place. If this happens we just need to organize 5 options (3 couples and 2 singles) in 5 Places (3 for a couple and 2 for the singles)
It means that now there are just 5 Places in the row and 5 options to organized. So the number of ways can be calculated using a rule of multiplication as:
<u> 5 </u>*<u> 4 </u>* <u> 3 </u> * <u> 2 </u> * <u> 1 </u> = 120
1st place 2nd Place 3rd place 4th Place 5th Place
Because we have 5 options for the 1st Place, the three couples and the 2 singles. Then, 4 options for the second Place, 3 options for the third place, 2 for the fourth place and 1 option for the 5th place.
Finally, they can be seated in 120 differents ways.
martemat 20 e7 72gsys y3823 485 u
We could use the Pythagorean theorem for this kind of problem I think:
A^2 + B^2 = C^2
6^2 + 16^2 = C^2
36 + 256 = C^2
292 = C^2
17.08 = C
C = 17.1 to the nearest tenth
Sorry if it’s wrong and glad I could help if it’s right ❤️❤️ Take care!
Since grades are out of 100, you can just subtract 75 from 90 which is 15. the percent of increase in the student's grade is 15%
Answer:
do you need all work shown for this problem
