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Marizza181 [45]
4 years ago
8

Which case allows for more than one triangle with the given measures to be constructed?

Mathematics
1 answer:
Anni [7]4 years ago
7 0
<span>A.three sides measuring 9 meters, 5 meters, and 5 meters

--> only one isosceles triangle

B.three sides measuring 6 inches, 3 inches and 9 inches

--> none triangle may be formed because 9 = 3 + 6 and there is a rule (the triangle inequality theorem) that states the length of any side must be less than the sum of the lengths of other two sides.  

C.three angles measuring 25°, 25°, and 130°

--> 25 + 25 + 130 = 180 => you can construct many triangles with these angles

D.three angles measuring 55°, 25°, and 125°

--> 55 + 25 + 125 = 205 > 180 => you cannot construct any triangle with theses measures.
</span>
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A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa
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The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

8 \times h + 5 \times f = 24

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

6 \times h + 2 \times f = 16.60

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<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

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<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

<h3>h = 2.5</h3>

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

<h3>f = 0.8</h3>

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

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umka21 [38]
I THINK the answer is 5.
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