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Travka [436]
3 years ago
6

Y = 10x + 6 sollve this by doing what

Mathematics
1 answer:
Vladimir79 [104]3 years ago
6 0

Answer:

x = -3/5

Step-by-step explanation:

y = 10x + 6

0 (- 6) = 10x + 6 (- 6)

-6/10 = 10x/10

-6/10 = x

-3/5 = x

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If 32^2c= 8^c+7, what is the value of c
Leona [35]

\bf 32^{2c}=8^{c+7}~~ \begin{cases} 32=2\cdot 2\cdot 2\cdot 2\cdot 2\\ \qquad 2^5\\ 8=2\cdot 2\cdot 2\\ \qquad 2^3 \end{cases}\implies (2^5)^{2c}=(2^3)^{c+7} \\\\\\ 2^{5(2c)}=2^{3(c+7)}\implies \stackrel{\textit{if the bases are the same, then so are the exponents}}{5(2c)=3(c+7)\implies 10c=3c+21} \\\\\\ 7c=21\implies c=\cfrac{21}{7}\implies c=3

3 0
3 years ago
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A play station costs $500, but you want to only pay $450. How much discount in percents do you want?
Alexus [3.1K]

Answer:

You only want a 10% discount...

500 - 450 = 50  

50/500 = 1/10 = .1 = 10%

4 0
3 years ago
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IMPOSSIBLE PLEASE HELP! ALSO MAKE SURE TO WRITE A LET STATEMENT
madam [21]
Q1 :
x + (x+25) = 131
2x + 25 = 131
2x = 131-25
2x = 106
x = 53
53+25 = 78
Therefore, 53+78=131

Q2 :
x + (x+14) = 58
2x + 14 = 58
2x = 58-14
2x = 44
x = 22
22+14 = 36
Therefore, 22+36=58

Q3 :
let ‘b’ be basketball
b + (3+b) = 27
2b + 3 = 27
2b = 27-3
2b = 24
b = 12
12 + 3 = 15
Therefore, 12 + 15 = 27
12 basketballs and 15 footballs were sold on Saturday

Q4 :
let ‘s’ be soup
s + 2s = 738
3s = 738
s = 246
246 x 2 = 492
Therefore, the hamburger has 492 calories while the soup as 246 calories

hope it helps somehow!

4 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdt%7D%20%3Dky" id="TexFormula1" title=" \frac{dy}{dt} =ky" alt=" \frac
sladkih [1.3K]

This ODE is separable; we have

\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt

Integrating both sides gives a general solution of

\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}

B is the only choice that is applicable.

4 0
4 years ago
Fatoring Trinomials<br> x^2+2x=-1
Musya8 [376]

Answer:

\Huge \boxed{x=-1}

Step-by-step explanation:

x^2+2x=-1

Adding 1 to both sides of the equation.

x^2+2x+1=-1+1

x^2 +2x+1=0

Factoring the left side of the equation.

x^2 +1x+1x+1=0

x(x+1)+1(x+1)=0

(x+1)(x+1) = 0

(x+1)^2 =0

Taking the square root of both sides of the equation.

\sqrt{(x+1)^2} =\sqrt{0}

x+1=0

Subtracting 1 from both sides of the equation.

x+1-1=0-1

x=-1

8 0
3 years ago
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