Answer: ||, |||, |
Step-by-step explanation:
Given that Segments UV and WZ are parallel with line ST intersecting both at points Q and R respectively.We prove that corresponding angles are congruent as follows: Statements Reasons
segment UV is parallel to segment WZ Given Points S, Q, R, and T all lie on the same line. GivenII.) m∠SQT = 180° Definition of a Straight AngleIII.) m∠SQV + m∠VQT = m∠SQT Angle Addition Postulate I.) m∠SQV + m∠VQT = 180° Substitution Property of Equalitym∠VQT + m∠ZRS = 180° Same-Side Interior Angles Theorem
m∠SQV + m∠VQT = m∠VQT + m∠ZRS Substitution Property of Equality
m∠SQV + m∠VQT − m∠VQT = m∠VQT + m∠ZRS − m∠VQT
m∠SQV = m∠ZRS Subtraction Property of Equality
∠SQV ≅ ∠ZRS Definition of Congruency Therefore, the most logical order of statements and reasons I, II, and III to complete the proof is ||, |||, |. I hope this helped.
Answer:
2(x+5)=2x-3
2x+10=2x-3
2x-2x= -3-10
0= -13
Step-by-step explanation:
Answer:
35
Step-by-step explanation:
what you gotta do is multiply 5 * 7 to get 35
Answer:
Part A: Options D and E
Part B: Disagree
Step-by-step explanation:
Part A:
From the graph attached,
Option A
The object is launched from the ground.
False.
Since, the object is launched from the 5 feet above the ground.
Option B
The flight is symmetric about the line t = 10
False.
Since, the flight is symmetric about the line t = 12
Option C
The object reaches a maximum height of 12 feet.
False.
At t = 12 seconds maximum height of the object = 19.4 feet
Option D
The object is flying in the air during the interval 0 < t < 25.93
True.
Option E
The object reaches its maximum height after 12 seconds of flight.
True.
After 12 seconds object is at the maximum height 19.4 feet.
Therefore, Options D and E are the correct options.
Part B:
From the table attached,
h(4) = 13
h(20) = 13
At t = 4 and 13 seconds height of the object is same.
h(4) = h(20)
But Timothy said h(4) < h(20)
Therefore, disagree with the statement of Timothy.
