Question

Find all the numbers such that the number added to itself is less than the number subtracted from 6

Answer 1

Answer:

All numbers less than 2 or $(-\infty, 1]$ or $(-\infty, 2)$

Step-by-step explanation:

Given that:

Number is added to itself is less than the number subtracted from 6.

To find:

All such numbers.

Solution:

Let the number be $x$.

Here, an inequality will be made.

When solved, it might give more than one answers.

As per the question statement, let us write the inequality.

Number added to itself $\Rightarrow x +x =2x$

Number subtracted from six = $6-x$

As per question:

$2x$

So, the answer is:

All numbers less than 2 or $(-\infty, 1]$ or $(-\infty, 2)$.