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AlekseyPX
3 years ago
11

Solving a quadratic equation when a is not equal to 1 by completing the square:

Mathematics
1 answer:
LenKa [72]3 years ago
5 0
<h3>Answer:</h3>

x² -6x = -13 ⇒ x ∈ {3-2i, 2+2i}

<h3>Step-by-step explanation:</h3>

To make a=1, divide the equation by the coefficient of x², which is 8.

... x² -6x = -13 . . . . . . your blanks are filled with -6 and -13

Now, to complete the square, add the square of half the x-coefficient:

... (-6/2)² = 9.

... x² -6x +9 = -4 . . . 9 added to both sides

... (x -3)² = -4 . . . . . rewrite as a square

... x -3 = ±2i . . . . . . take the square root

... x = 3 ±2i . . . . . . . add 3

The solutions are the complex numbers x = 3 ±2i.

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