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4 years ago

14

Please help will give brainliest

1 answer:

Kruka [31]4 years ago

7 0

X and y vary inversely:
y=C/x, where C is a constant

x=2 when y=7→7=C/2

Solving for C:
2(7)=C
14=C
C=14

y=C/x
y=14/x

Answer: Second option: y=14/x

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There are 4 king in standard deck of 52 cards l.Id a card was chosen at random what is the probability of selecting a card that

ELEN [110]

The answer is 12/13 in fraction form or 92% as a percent

4 0

3 years ago

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What is 5/12 of 2/5 i need help

Marianna [84]

Answer:10/60

If need to simply it is 1/6.

Step-by-step explanation: Mutiply 5/12 by 2/5 .

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3 years ago

WILL MARK AS BRAINLIEST A slice is made perpendicular to the base of a right rectangular prism as shown.

Likurg_2 [28]

Hi, here is the correct answer <3

Answer:

A rectangle.

Step-by-step explanation:

Since the cross-section will be perpendicular to the base, it is parallel to the lateral faces of the prism. This means it will be the same shape as the lateral faces.

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3 years ago

X/2−5=−12<br> I need to know how to get the answer to what X is

QveST [7]

Answer:

-14

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x/2-5=-12

1/2x+-5=-12

1/2x-5=-12

Step 2: Add 5 to both sides.

1/2x-5+5=-12+5

1/2x=-7

Step 3: Multiply both sides by 2.

2*(1/2x)=(2)*(-7)

x=-14

8 0

3 years ago

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Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

3 years ago