Answer:
ther will be exactly one value. the answer is b
First you need to get a common denominator. The first two problems already have a common denominator, so you just have to find the sum and difference of the two problems, respectively.
6.) (9y-3)/(y^2-5)
8.) 3/xy^3
Two find a common denominator, find the smallest value that has BOTH denominators as factors.
10.) 8x^3*y^3 is the common denominator
Answer: 2/(8*x^3*y^3)
12.) Factor x^2 + 4x + 4 to get (x+2)(x+2)
Therefore, x+2 is already part of x^2 + 4x + 4
(x+4)/(x^2+4x+4)
14.) Factor both denominators..
4(y+2) and y(y+2)
So the common denominator would be 4y(y+2)
The first fraction is missing a "y" so multiply the numerator by y to get y^2
The second fraction is missing a "4" so multiply the numerator by 4 to get 4
(y^2 - 4)/(4y(y+2))
So can factor the numerator to get (y+2)(y-2). There if a (y+2) on top and bottom so they cancel out.
Answer: (y-2)/4y
Answer:
0.0668 or 6.68%
Step-by-step explanation:
Mean time (μ)= 46 minutes
Standard deviation (σ) = 6 minutes
The z-score for any given time X is determined by:
For X = 37:
A z-score of -1.5 corresponds to the 6.68th percentile of a normal distribution. The probability that it will take less than 37 minutes to complete the test is
The probability is 0.0668 or 6.68%
Answer:+3i or -3i
Step-by-step explanation:
±√(-36)=+√(-36) or -√(-36)
+√(-1)×√(36) or -√(-1)×√(36) √(-1)=i
+i×6 or -i×6=+6i or -6i
Dividing by 2 we get
+6i/2 or -6i/2=+3i or -3i
<em>Hey</em><em>!</em><em>!</em>
<em>Ques</em><em>tion</em><em>:</em><em> </em><em>The</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>three</em><em> </em><em>times</em><em> </em><em>'y'</em><em> </em><em>and</em><em> </em><em>1</em><em>1</em><em> </em><em>is</em><em> </em><em>3</em><em>2</em>
<em>Answer</em><em>:</em><em> </em><em>3</em><em>y</em><em>+</em><em>1</em><em>1</em><em>=</em><em>3</em><em>2</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
