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Paraphin [41]
3 years ago
13

the length of a rectangle is 5 inches more then the width. the area of the rectangle is equal to 2 inches more than 4 times the

perimeter. Find the length and width of the rectangle
Mathematics
1 answer:
Svet_ta [14]3 years ago
5 0
P = 2(L + W)
L = W + 5
A = 4P + 2

P = 2(W + 5 + W)
P = 2(2W + 5)
P = 4W + 10

A = 4P + 2
A = 4(4W + 10) + 2
A = 16W + 42

A = L * W
A = W(W + 5)
A = W^2 + 5W

W^2 + 5W = 16W + 42
W^2 + 5W - 16W - 42 = 0
W^2 - 11W - 42 = 0
(W + 3)(W - 14) = 0

W - 14 = 0
W = 14 <==

L = W + 5
L = 14 + 5
L = 19 <==

P = 2(19 + 14)
P = 2(33)
P = 66

A = L * W
A = 19 * 14
A = 266

answer : length = 19, width = 14....perimeter = 66....area = 266
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Step-by-step explanation:

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If r(x) = 3x – 1 and s(x) = 2x 1, which expression is equivalent to (startfraction r over s endfraction) (6)? startfraction 3 (6
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The expression which is equivalent to the given ratio of the two provided binary fraction is startfraction 3 (6) minus 1 over 2 (6) 1 endfraction.

<h3>What is the equivalent expression?</h3>

Equivalent expressions are the expression whose result is equal to the original expression, but the way of representation is different.

The given binary functions are.

r(x) = 3x - 1

s(x) = 2x +1

The expression which has to be found out is,

\left(\dfrac{r}{s}\right)(6)=\left(\dfrac{3(6)-1}{2(6)+1}\right)\\\left(\dfrac{r}{s}\right)(6)=\left(\dfrac{18-1}{12+1}\right)\\\left(\dfrac{r}{s}\right)(6)=\left(\dfrac{17}{13}\right)

Thus, the expression which is equivalent to the given ratio of the two provided binary fraction is startfraction 3 (6) minus 1 over 2 (6) 1 endfraction.

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brainly.com/question/2972832

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