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Paraphin [41]
3 years ago
13

the length of a rectangle is 5 inches more then the width. the area of the rectangle is equal to 2 inches more than 4 times the

perimeter. Find the length and width of the rectangle
Mathematics
1 answer:
Svet_ta [14]3 years ago
5 0
P = 2(L + W)
L = W + 5
A = 4P + 2

P = 2(W + 5 + W)
P = 2(2W + 5)
P = 4W + 10

A = 4P + 2
A = 4(4W + 10) + 2
A = 16W + 42

A = L * W
A = W(W + 5)
A = W^2 + 5W

W^2 + 5W = 16W + 42
W^2 + 5W - 16W - 42 = 0
W^2 - 11W - 42 = 0
(W + 3)(W - 14) = 0

W - 14 = 0
W = 14 <==

L = W + 5
L = 14 + 5
L = 19 <==

P = 2(19 + 14)
P = 2(33)
P = 66

A = L * W
A = 19 * 14
A = 266

answer : length = 19, width = 14....perimeter = 66....area = 266
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If 12% = 1000, what is the remaining 88% worth?
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Note: I am not 100% sure that this is the correct way to solve this problem. It is just my best attempt to help. 

Keep in mind that every percentage can be made into a decimal. 12% = 0.12 because 12% is also 12/100 as a fraction.

Since a percentage is the original number multiplied by the percent, you can solve this problem by dividing the number given by the percent. Be sure to turn the percent into a decimal to make it easier. Your work should look like this:

12% = 0.12

1,000 / 0.12 = 8,333.33

That is the first step. How you have to finish the problem and find what 88% is. To do this, you can simply multiply 88%, or 0.88, times the answer you get in the first part. Your work should look like this:

88% = 0.88
0.88 * 8,333.33 = 7,333.33 

Now to check your work, you can add 7,333.33 and 1,000 to see if it equal the total of 8,333.33

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