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4 years ago

Approximate ∛-25 to the nearest tenth.

2 answers:

4 0

Even without a calculator, it is possible to estimate the cube-root of -25 if you know a little about differential calculus and the Newton's rule, which says that given a close-enough approximation x0 to the cube-root of -25, a better approximation x1 is given by

x1=x0-(x0^3-(-25))/(3x0^2)

Say we have an initial approximation of x0=-3, since (-3)^3=-27, not far from -25.

A closer approximation is then

x1=-3-((-3)^3-(-25))/(3*(-3)^2)=-3-(-2/27)=-3+0.074=-2.926

which is accurate to the second digit without using a calculator, using all integer calculations and 2 one digit divisions.

So the final answer is -2.9 (accurate to one decimal place)

(note 2/27=(2/9)/3 = 0.22222222.../3=0.07407..., which can be handled without pencil and paper)

tangare [24]4 years ago

3 0

-2.92401773821 ≅ -2.9

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∠ACB is inscribed in semicircle ACB of a circle with centre O then m∠ACB =

Zolol [24]

<h2>Answer:</h2>

[C] 90°.

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3 years ago

Read 2 more answers

If a || b and m1 = 65°, what is m2? m2 = ______

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Answer:

M2=65

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These two are congruent

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3 years ago

A standard number cube, numbered 1 through 6 on each side, is rolled 3 times. What is the probability of rolling a 2 on all thre

nikklg [1K]

Answer:

The answer is 1/216

Step-by-step explanation:

The probability of getting a 2 on a six-sided number cube is 1/6 because the number "2" appears on just one out of the six faces.

Since, the probability of getting a 2 in the first throw is independent of the probability of getting a 2 in the subsequent throws, we multiply these probabilities:

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P = 1/216

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3 years ago

Multiply the polynomial (4d-3)(-2d+1)

Nutka1998 [239]

If this an it my bad Gee

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3 years ago

Please help with this asappppppppll

Alenkinab [10]

We are given with a circle and we need to find the equation of the circle , but first let's recall that , the equation of a circle with radius 'r' and centre at (h,k) is given by ${\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}$

Now , here as as the circle cuts the +ve x-axis at (9,0) . So , it's radius is 9 units or the 2nd way is to measure the distance from centre of the circle to the point where the circle cuts the graph , as the centre is at Origin , so here (h,k) = (0,0) .Which means that the centre is located at the point whose coordinates are (0,0) which is also known as origin . Now , finding the equation of the circle :-

${:\implies \quad \sf (x-0)^{2}+(y-0)^{2}=(9)^{2}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{x^{2}+y^{2}=81}}}$

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7 0

3 years ago