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arsen [322]
3 years ago
12

If two objects are moved closer together so that the distance between them is one-third the original distance, what is the gravi

tational force after the objects are moved?
one-ninth the original gravitational force
one-third the original gravitational force
three times the original gravitational force
nine times the original gravitational force

Physics
2 answers:
Helga [31]3 years ago
6 0
Nine times the original gravitational force
r-ruslan [8.4K]3 years ago
3 0
Answer:
nine times the original gravitational force
Explanation:
The rule of the gravitational force between two bodies is shown in the attached images.
The parameters in the rule are:
Fg : the gravitational force between the two bodies
G : universal gravitational constant
m1 and m2 : the masses of the two bodies
r : the distance between the two bodies

From the given rule, we can notice that:
The force of attraction between the two bodies is inversely proportional to the square of the distance between them.
This means that:
As the distance decreases to 1/3 its original value, the gravitational force would increase by a factor of 9. 

Hope this helps :)

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A spring is 14cm long. Three masses are hung from it and then it is measured again. Now it is 19.5cm long. What force did the th
lukranit [14]

Answer:

Gravity

Explanation:

The answer is gravity because when the 3 masses were hung from the spring, gravity pulled the spring towards the ground.

3 0
3 years ago
If the rifle is stopped by the hunter's shoulder in a distance of 3.23 cm, what is the magnitude of the average force exerted on
never [62]

By conservation of momentum, the initial recoil speed of the rifle is: 
u = 904kg * 0.0106 kg / 3.53 kg = 2.7146 m/s 

The final recoil speed v is zero in a distance of d = 0.0346 m 

So the rifle's acceleration is a = (0 - u^2) / 2*d = -2.7146^2 / 2*.0323 m/s^2 
a = -114.07m/s^2 

6 0
3 years ago
You have two resistors with the same cross sectional area and resistivity. Resistor A has length L1 and resistor B has length L2
oee [108]

Answer:

Explanation:

Given

Resistor A has length L_1

and Resistor B has Length L_2

and Resistance is given by

R=\frac{\rho L}{A}

Considering \rhoand A to be constant thus

R_2>R_1 because L_2>L_1

(a)When they are connected in series

As the current in series is same and power is i^2R

therefore P_2>P_1 as R is greater for second resistor

(b)if they are connected in Parallel

In Parallel connection Voltage is same

P=\frac{V^2}{R}

resistance of 2 is greater than 1 thus Power delivered by 1 is greater than 2

8 0
3 years ago
You have a mass of 55kg and are riding your frictionless skateboard, which has a mass of 5kg, in a straight line at a speed of 4
Rzqust [24]

Given

m1(mass of the first object): 55 Kg

m2 (mass of the second object): 55 Kg

v1 (velocity of the first object): 4.5 m/s

v2 (velocity of the second object): ?

m3(mass of the object dropped): 2.5 Kg

The law of conservation of momentum states that when two bodies collide with each other, the momentum of the two bodies before the collision is equal to the momentum after the collision. This can be mathemetaically represented as below:

Pa= Pb

Where Pa is the momentum before collision and Pb is the momentum after collision.

Now applying this law for the above problem we get

Momentum before collision= momentum after collision.

Momentum before collision = (m1+m2) x v1 =(55+5)x 4.5 = 270 Kgm/s

Momentum after collision = (m1+m2+m3) x v2 =(55+5+2.5) x v2

Now we know that Momentum before collision= momentum after collision.

Hence we get

270 = 62.5 v2

v2 = 4.32 m/s




7 0
3 years ago
A tuning fork is held over a resonance tube, and resonance occurs when the surface of the water is 12 cm below the top of the tu
Rainbow [258]

Answer:

786 Hz

Explanation:

Recall, the speed of sound is

v = 332 + 0.6t

Where t = 23°

v = 332 + 0.6(23)

v = 332 + 13.8

v = 345.8 m

Also, it is known that distance between two consecutive resonance length is half of the wavelength.

L2 - L1 = λ/2

34 - 12 = λ/2

λ/2 = 22

λ = 44 cm

Finally, remember that also

Frequency = speed/ wavelength

Frequency = 345.8/0.4

Frequency = 786 Hz

Therefore, the frequency of the tuning fork is 786 Hz

6 0
3 years ago
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