All are forms of electromagnetic radiation. hope this helps!
Answer: The spring potential energy must equal or exceed the energy to raise the mass to loop height and the minimum kinetic energy needed to keep the mass in contact with the top of the loop
kd² = 5Mrg
h = kd²/2Mg
Explanation:
at top of loop
Mv²/r = Mg
v² = rg
½kd² = ½Mv² + Mgh'
½kd² = ½M(rg) + Mg(2r)
½kd² = 2.5Mrg
kd² = 5Mrg
½kd² = Mgh
h = kd²/2Mg
Answer:
The bowling ball
Explanation:
The PE (gravitational potential energy) of an object is given by:

where
m is the mass of the object
g is the gravitational acceleration
h is the height of the object above the ground
In this case, we are comparing the PE of a bowling ball and of a ping pong ball. The two balls are located at same height (h=5 m) and the gravitational acceleration is the same (g=9.8 m/s^2), so their PE depends only on their mass: since the bowling ball has a greater mass than the ping pong ball, the bowling ball will have a greater PE.
Answer:
Aluminum (Al)
Explanation:
1. You wrap a sandwich in aluminum foil
2. Aluminum is on the periodic table.
Answer:
15 deg
Explanation:
Assume both snowballs are thrown with the same initial speed 27.2 m/s. The first snowball is thrown at an angle of 75◦ above the horizontal. At what angle should you throw the second snowball to make it hit the same point as the first? The acceleration of gravity is 9.8 m/s 2 . Answer in units of ◦ .
Given:
For first ball, θ1 = 75◦
initial velocity for both the balls, u = 27.2 m/s
for second ball, θ2 = ?
since distance covered by both the balls is same.
Therefore,..
R1=(u^{2} sin2\alpha _{1}) /g[/tex]
the range for the first ball
the range for the second ball
R2=(u^{2} sin2\alpha _{2}) /g[/tex]
(u^{2} sin2\alpha _{2}) /g[/tex]=(u^{2} sin2\alpha _{1}) /g[/tex]
sin2\alpha _{2})=sin2\alpha _{1})
=sin^-1(sin2\alpha _{1})
=1/2sin^-1(sin2\alpha _{1})
=
15 deg