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Troyanec [42]
3 years ago
12

Force (N) = 250 Mass (kg) = 221 Acceleration (m/s^2) = ?

Physics
1 answer:
lyudmila [28]3 years ago
8 0

Answer:

The required acceleration is a=1.1 m/s²

Explanation:

Given

  • Force F = 250 N
  • Mass m = 221 kg

To determine

Acceleration a = ?

We know that acceleration is produced when a force is applied to a body.

The acceleration can be determined using the formula

F = ma

where

  • F is the force
  • m is the mass
  • a is the acceleration

now substituting F = 250 , and m = 221 in the formula

F = ma

250 = 221 (a)

switch the equation

221(a) = 250

Divide both sides by 221

\frac{221a}{221}=\frac{250}{221}

simplify

a=\frac{250}{221}

a=1.1 m/s²

Therefore, the required acceleration is a=1.1 m/s²

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In April 1974, Steve Prefontaine completed a 10.0 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.43 km mark a
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Answer:

Acceleration, a = 0.101 m/s²

Explanation:

Average speed = total distance / total time.

At the 7.43km mark, total distance = 7.43km or 7430m

Total time = 25 * 60 s = 1500s

Average speed = 7430m/1500s = 4.95m/s

He then covers (10 - 7.43)km = 2.57 km = 2570 m

in t = 27m43.6s - 25min = 2m43.6s = 163.6 s

Then he accelerates for 60 s, and maintains this velocity V, for the remaining (163.6 - 60)s = 103.6 s.

From V = u + at; V = 4.95m/s + a *60s

Distance covered while accelerating is

s = ut + ½at² = 4.95m/s * 60s + ½ a *(60s)² = 297m + a*1800s²

Distance covered while at constant velocity, v after accelerating is

D = velocity * time

Where v = 4.95m/s + a*60s

D = (4.95m/s + a*60s) * 103.6s = 512.82m + a*6216s²

Total distance covered after initial 7.43 km, S + D = 2570 m, so

2570 m = 297m + a*1800s² + 512.82m + a*6216s²

2570 = 809.82 + a*8016

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If a car moves with constant velocity, does it also move with a constant speed?
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Answer:

Yes. The fact that an object moves at constant velocity implies that its speed is also constant. Note that the converse statement isn't necessarily true.

Explanation:

Velocity is a vector. For two vectors to be equal to each other,

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In motions, the magnitude of an object's velocity is the same as its speed.

If the car moves with a constant velocity, that means that

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In other words,

\text{Velocity } \vec{v}\text{ is constant} \implies \text{Speed }v\text{ is constant}.

Note that the arrow here points only from the velocity side to the speed side. It doesn't point backward because knowing that the speed of an object is constant won't be sufficient to prove that the velocity of the object is also constant. For example, for an object in a uniform circular motion, the speed is constant but the direction keeps changing. Hence the velocity isn't constant.

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