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ale4655 [162]
3 years ago
5

I need help with 29, 32, 35, 38, 43, 46, 49, 44, 47, 50. ASAP

Mathematics
1 answer:
gogolik [260]3 years ago
7 0
29. d=-4
32. h=45
35. n=76
38. t=5
43. x=-11
46. x≈0.7
47. x≈1.6
49. d=-2
50. t=1/2

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Charra [1.4K]
Not sure if you’re speaking Spanish or not but yes
5 0
2 years ago
EXPERTS PLEASE HELP!!!!!!!!!!!!!!
Arturiano [62]

Answer:

1. D

2. x=65

Step-by-step explanation:

Hi!

Your answer is D because 78 is 120% of x

120% in decimal point is 1.2.

So it's 1.2x is the same as 120% of x

For question 8:

1.2x=78

Isolate x by divide 1.2 on both sides

78/1.2=65

7 0
2 years ago
The ratio of triangle abc to the corresponding side of similar triangle def is 3:5. the perimeter of triangle def is 48in. what
Vlad1618 [11]
ABC : DEF
3: 5
3 x 9.6 : 5 x 9.6
28.8 : 48
Perimeter of triangle ABC = 28.8 inch
7 0
3 years ago
How would you solve 3x^2-12=0?
Gennadij [26K]

                                                                                 3x^2 - 12  =  0

Personally, I would divide each side by 3                x^2 - 4  =  0

Then I would add 4 to each side                              x^2        =  4

Then I would take the square root of each side:     x  =  +4
                                                                                     x  =  -4 .

Having found both solutions, I would relax with a cup of tea.

3 0
3 years ago
Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0
3 years ago
Read 2 more answers
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