In order to prove the triangle is a right angled triangle we need to prove that the slope of the lines CA and BC and AB have any negative reciprocals.Lets find the slopes .
AB=(-1,3), (1,2) slope of AB = 2-3/1-(-1)= -1/2 slope of AB is -1/2
BC = (1,2), (-3,1) slope of BC is 1-2/-3-1= -1/-4 slope of BC is 1/4
Slope of CA =(-3,1)(-1,3) slope of 3-1/-1-(-3)=-2/-2=1
Since the slopes do not have any negative reciprocals so the triangle is not a right angled triangle
Answer:
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Answer:
(-2, 1)
Step-by-step explanation:
consider the following equations: -x-y=1 y=x+3
For the lines to intersect, the values must be the same
-x-y=1
x + y = -1
y = -x - 1
Equating the y values
-x - 1 = x+ 3
-x-x = 3 + 1
-2x = 4
x = 4/-2
x = -2
Substitute x = -2 into y = x+3
y = -2 + 3
y = 1
Hence the required coordinate is (-2, 1)
Answer:
slope = 2
Step-by-step explanation:
Calculate the slope m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 8) and (x₂, y₂ ) = (- 4, 0)
m = 
= 
= 2
Answer:
rise
Step-by-step explanation:
