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3 years ago

Please help give bralienst not need explation

Mathematics

2 answers:

Alecsey [184]3 years ago

7 0

Answer:

4.5 cm

Step-by-step explanation:

The ruler says it all..... (why do you need help with this? What grade????)

Hope this helps, have a good day :)

Setler [38]3 years ago

6 0

Answer:Its 4.5 centimeters

Step-by-step explanation:

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There are 150 students at the zoo. 90 of the students visited the gorilla

olga55 [171]

Divide the number that visited the gorilla by the total students at the zoo then multiply by 100

90/150 = 0.6

0.6 x 109 = 60%

The answer is 60%

7 0

3 years ago

Read 2 more answers

A house cost $120,000 when it was purchased. The value of the house increases by 10% each year. Find the rate of growth each mon

olga_2 [115]

FIRST MODEL:

Well the model for the value of the house is:

$V={ \left( \frac { 11 }{ 10 } \right) }^{ t }\cdot 120000$

V = Value

t = Years passed {t≥0}

-----------------------

When t=0, V=120000

When t=1, V=132000

When t=2, V=145200

etc... etc...

---------------------------

Now, this model is actually curved so there is no constant rate of growth each month. We can only calculate what the rate of growth is at a particular time. If we want to find out the rate of growth at a particular time, we must differentiate the formula (model) above.

--------------------------

$V={ \left( \frac { 11 }{ 10 } \right) }^{ t }\cdot 120000\\ \\ \ln { V=\ln { \left( { \left( \frac { 11 }{ 10 } \right) }^{ t }\cdot 120000 \right) } }$

$\\ \\ \ln { V=\ln { \left( { \left( \frac { 11 }{ 10 } \right) }^{ t } \right) } } +\ln { \left( 120000 \right) } \\ \\ \ln { V=t\ln { \left( \frac { 11 }{ 10 } \right) } } +\ln { \left( 120000 \right) }$

$\\ \\ \frac { 1 }{ V } \cdot \frac { dV }{ dt } =\ln { \left( \frac { 11 }{ 10 } \right) } \\ \\ V\cdot \frac { 1 }{ V } \cdot \frac { dV }{ dt } =\ln { \left( \frac { 11 }{ 10 } \right) } \cdot V$

$\\ \\ \therefore \quad \frac { dV }{ dt } =\ln { \left( \frac { 11 }{ 10 } \right) } \cdot { \left( \frac { 11 }{ 10 } \right) }^{ t }\cdot 120000$

Plug any value of (t) that is greater than 0 into the formula above to find out how quickly the investment is growing. If you want to find out how quickly the investment was growing after 1 month had passed, transform t into 1/12.

The rate of growth is being measured in years, not months. So when t=1/12, the rate of growth turns out to be 11528.42 per annum.

SECOND MODEL (What you are ultimately looking for):

$V={ \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } }\cdot 120000$

V = Value of house

t = months that have gone by {t≥0}

Formula above differentiated:

$V={ \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } }\cdot 120000\\ \\ \ln { V } =\ln { \left( { \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } }\cdot 120000 \right) }$

$\\ \\ \ln { V=\ln { \left( { \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } } \right) } } +\ln { \left( 120000 \right) }$

$\\ \\ \ln { V=\frac { t }{ 12 } } \ln { \left( \frac { 11 }{ 10 } \right) } +\ln { \left( 120000 \right) }$

$\\ \\ \frac { 1 }{ V } \cdot \frac { dV }{ dt } =\frac { 1 }{ 12 } \ln { \left( \frac { 11 }{ 10 } \right) }$

$\\ \\ V\cdot \frac { 1 }{ V } \cdot \frac { dV }{ dt } =\frac { 1 }{ 12 } \ln { \left( \frac { 11 }{ 10 } \right) } \cdot V$

$\\ \\ \therefore \quad \frac { dV }{ dt } =\frac { 1 }{ 12 } \ln { \left( \frac { 11 }{ 10 } \right) } \cdot { \left( \frac { 11 }{ 10 } \right) }^{ \frac { t }{ 12 } }\cdot 120000$

When t=1, dV/dt = 960.70 (2dp)

dV/dt in this case will measure the rate of growth monthly. As more money is accumulated, this rate of growth will rise. The rate of growth is constantly increasing as the graph of V is actually a curve. You can only find out the rate at which the house value is growing monthly at a particular time.

6 0

3 years ago

25 children are standing in a line to play a game. they are given numbers 1 to 25 to identify themselves. then, every 4th child

MrRa [10]

Children who came forward are numbered 4, 8, 12, 16, 20, 24 i.e. multiples of 4 ≤25

Given that 25 kids are waiting in line to play a game. They are assigned numbers ranging from 1 to 25 to identify themselves. Then, every fourth child in line is asked to step forward.

Every fourth child in the line is asked to step forward

then, 4th child,8th child,12th child,16th child,20th child,24 child will come forward as if 4,8,12,16,20,24 are the numbers which are multiples of 4 ≤25

Children who came forward are numbered 4, 8, 12, 16, 20, 24 i.e. multiples of 4 ≤25

Learn more about numbers here:

brainly.com/question/17429689

#SPJ4

8 0

1 year ago

What is the value of the digit five in this number 58

vlada-n [284]

The five is in the tenth place so it is 50

3 0

3 years ago

Read 2 more answers

PLSS HELP ASAP TYSM <33 SORRY I COULDN'T FIND SCIENCE LOLL

dimaraw [331]

Answer:

Rock D.

Step-by-step explanation:

We can assume that the force that the catapult does is always the same.

So, here we need to remember Newton's second law:

F = m*a

force equals mass times acceleration.

Where acceleration is the rate of change of the velocity.

So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.

So, we can rewrite:

a = F/m

So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.

Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.

So we can assume that rock D is the correct option.

5 0

3 years ago