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3 years ago

Which Rule describes the composition of transformations that maps figure PQRS to figure P”Q’R”S”?

Mathematics

2 answers:

stiv31 [10]3 years ago

6 0

Answer:

I THINK THE SECOND ONE

Step-by-step explanation:

Serjik [45]3 years ago

6 0

Answer:

Choice B is correct. Just took the test.

Step-by-step explanation:

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The basket of golf balls at a miniature golf course contains 18 golf balls. 4 are yellow, 6 are blue, 2 are red, and the rest ar

Aneli [31]

Answer: 33.3%

Step-by-step explanation:

First find the number of green balls in the basket:

= Total - yellow - blue - red

= 18 - 4 - 6 - 2

= 6 balls

The probability of picking a green ball can be found by the formula:

= Number of green balls / Number of total balls

= 6 / 18

= 33.3%

7 0

3 years ago

Find the slope of the line that passes through the given points.<br> (7,3) and (13,8)

Trava [24]

Answer:

$\frac{5}{6}$

Step-by-step explanation:

To find the slope, use the equation to find slope. The picture below shows what it looks like.

Using the equation, substitute the values in the x and y values.

$\frac{8-3}{13-7}$

Then solve

$\frac{5}{6}$

4 0

3 years ago

The cone and cylinder below have equal surface area

marissa [1.9K]

Answer:

Option B, False

Step-by-step explanation:

<u>Step 1: Get the surface area formulas for both shapes</u>

Surface Area Formula for Cone: $A = \pi * r(r + \sqrt{h^{2} + r^{2}})$

Surface Area Formula for Cylinder: $A = 2\pi rh+2\pi r^{2}$

<u>Step 2: Plug in the values and solve</u>

Cone: $A = \pi * r(r + \sqrt{(3r)^{2} + r^{2}})$

Cone: $A = \pi r^{2} + \pi \sqrt{10}r^{2}$

Cylinder: $A = 2\pi r*r+2\pi r^{2}$

Cylinder: $A=4 \pi r^{2}$

<u>Step 3: Compare</u>

<u /> $\pi r^{2} + \pi \sqrt{10}r^{2}\neq 4 \pi r^{2}$

They are not equal, therefore the answer is False.

Answer: Option B, False

6 0

2 years ago

What is the absolute value of the following complex number?<br> -4 + 4

snow_lady [41]

Answer:

Itz 0 if I am not wrong

hope it helps

3 0

3 years ago

Read 2 more answers

Test the four possible vertices that you found in the objective function in part A. Use those values to determine which set of v

irga5000 [103]

The testing of the four vertices of the objective function gives;

C(5, 0, 55) = 430

C(5, 30, 25) = 400

C(15, 30, 15) = 420

C(45, 0, 15) = 510 (maximum)

<h3>How to test objective functions?</h3>

The objective function is seen as attached.

Now, it is noticed that just two of the vertices are listed. The other two vertices are intersections of x + y + z = 60 with x = 5 and the constraints on y.

We will assume that; 0 ≤ y ≤ 30

Thus, the missing vertices are;

(x, y, z) = (5, 0, 55) and (5, 30, 25)

The two given vertices are;

(x, y, z) = (15, 30, 15) and (45, 0, 15)

Therefore, the objective function values are;

C(5, 0, 55) = 9·5 +6·0 +7·55 = 45 +0 +385 = 430

C(5, 30, 25) = 9·5 +6·30 +7·25 = 45 +180 +175 = 400

C(15, 30, 15) = 9·15 +6·30 +7·15 = 135 +180 +105 = 420

C(45, 0, 15) = 9·45 +6·0 +7·15 = 405 +0 +105 = 510

Read more about Objective Functions at; brainly.com/question/16826001

#SPJ1

5 0

1 year ago