Answer:
D is correct.
Step-by-step explanation:
We are given the root of the equation
If we are given solution of the equation then find equation using formula.
If a and b are the solution of equation then equation would be (x-a)(x-b)=0
Here,
Equation form would be
Now we simplify the above equation to get correct option.
So, D is correct.
Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end .
Step-by-step explanation:
Given:
Length of the pipe, = 120 cm
Its wavelength = 480 cm
= 160 cm and
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
So,
The fundamental wavelength:
⇒
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒ ⇒
⇒ ⇒
⇒ ⇒
⇒ ⇒
So the pipe is open at one end and closed at one end .