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3 years ago

Paul can type 60 words per min and jennifer can tpe 80 words per mi how does paul typeing speed compare to jenniffer

Mathematics

1 answer:

Semenov [28]3 years ago

8 0

Paul has a shorter typing speed than Jennifer

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Please help for brainliest

Ilya [14]

Answer:

D.No solution

Step-by-step explanation:

These two function are parallel (same slope) , so they would never intersect

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3 years ago

A single standard number cube is tossed. what is the probality of getting a 4 or 5?

xeze [42]

The probability would be 2/6 or 1/3

6 0

3 years ago

2 kitchen assistants can prepare 10 kg of vegetables in 60 minutes. How long would it take 15 assistants to prepare the same amo

Sonbull [250]

Then just one of them takes 2h.
<span>If you have 25 assistants, the time is 25 times less: 2/25 hours = 4.8 mins = 4 min and 48 sec.</span>

4 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago

The answer of this please? thank you for very much i really appreciate!

Zolol [24]

Answer:

77 degrees

Step-by-step explanation:

The interior angles of a triangle always add up to 180 degrees, so you can form an equation:

$x + 71 + 32 = 180$

$x + 103 = 180\\x = 77$

5 0

3 years ago