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Gemiola [76]
3 years ago
5

Examine the graphs and match each one with the correct coordinate rotation. You should match one graph with one rule.

Mathematics
1 answer:
irinina [24]3 years ago
8 0
A is with b d with a c with e
You might be interested in
Solve the equation 7x equals 42
Vikentia [17]
7x = 42

First, do the inverse operation.

The inverse of multiplication is division.

7x/7 = 42/7
x= 42/7
x= 6

Final answer: x= 6


7 0
4 years ago
Read 2 more answers
Which of the following is an arithmetic sequence?
enot [183]

Answer:

The third sequence.  

Step-by-step explanation:

In an arithmetic sequence, the difference between two consecutive terms is the same.

For each option, find the difference between consecutive terms:

First option:

  • 4 - 2 = 2.
  • 8 - 4 = 4.
  • 16 - 8 = 8.

The differences are not the same. As a result, this option is not an arithmetic sequence.

Second option:

  • 4 - 12 = -8.
  • \displaystyle \frac{4}{3} - 4 = -\frac{8}{3}.
  • \displaystyle \frac{16}{3} - \frac{4}{3} = \frac{12}{3} = 4.

The differences are not the same. As a result, this option is not an arithmetic sequence, either.

Third option:

  • \displaystyle -\frac{1}{2} - \frac{1}{2} = -1.
  • \displaystyle -\frac{3}{2} - \left(-\frac{1}{2}\right) = -\frac{3}{2} + \frac{1}{2} = -1.
  • \displaystyle -\frac{5}{2} - \left(-\frac{3}{2}\right) = -\frac{5}{2} + \frac{3}{2} = -1.

The differences are all -1. As a result, this option is indeed an arithmetic sequence. Its common difference is (-1).

Fourth option:

  • \displaystyle -\frac{1}{2} - \frac{1}{2} = -1.
  • \displaystyle \frac{1}{2} - \left(-\frac{1}{2}\right) = \frac{1}{2} + \frac{1}{2} = 1.
  • \displaystyle -\frac{1}{2}\right - \frac{1}{2} = -1.

The differences are varying between 1 and -1. As a result, this option is not an arithmetic sequence.

3 0
3 years ago
What is the sum of the polynomials?
kiruha [24]
I don’t see the picture
6 0
4 years ago
Which of the following graphs shows the solution set for the inequality below? 3|x + 1| < 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
3 years ago
What theorem or postulate can be used to justify that HIG=FIE
oksano4ka [1.4K]

Answer:

A

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
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