2 years ago

What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?k = a0

2 answers:

8 0

Answer:

Step-by-step explanation:

the answer is 3

5 0

F(x) = 112 - kx
f(-3) = 121

f(-3) = 112 - k(-3)
f(-3) = 112 + 3k
121 = 112 + 3k
121 - 112 = 3k
9 = 3k
9/3 = k
3 = k <===

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