V=3.14 5^2x15-3.14x2^2x15
=3.14x15(5^2-2^2) <—21
≈989. 601685
≈989.1 <—(3.14)
Step-by-step explanation:
since f'(x) = 2f(x) and f(3) has no term of x (so, there must be a constant that eliminates x for x = 3), we get
f(x) = x²/9 × c
c = m×e^n
f(1) = 1/9 × m×e^n = 5
=> m×e^n = 45
f(3) = 9/9 × m×e^n = 45
m = 45
n = 0
Answer:
b
Step-by-step explanation:
i did it yesterday
Take 400 and divided by 2 which u need 200 more people
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