4)

A 10.0-kg box starts at rest on a level floor. An external, horizontal force of 2.00 × 102 N is applied to the box for a distanc

Harman [31]

Answer:

vf = 11.2 m/s

Explanation:

m = 10 Kg

F = 2*10² N

x = 4.00 m

μ = 0.44

vi = 0 m/s

vf = ?

We can apply Newton's 2nd Law

∑ Fx = m*a (→)

F - Ffriction = m*a ⇒ F - (μ*N) = F - (μ*m*g) = m*a ⇒ a = (F - μ*m*g)/m

⇒ a = (2*10² N - 0.44*10 Kg*9.81 m/s²)/10 Kg = 15.6836 m/s²

then , we use the equation

vf² = vi² + 2*a*x ⇒ vf = √(vi² + 2*a*x)

⇒ vf = √((0)² + 2*(15.6836 m/s²)*(4.00m)) = 11.2 m/s

7 0

3 years ago

a group of students is asking people whether they use plastic bags. what are the students doing? a. stating a problem b. analyzi

notsponge [240]

I believe the correct answer from the choices listed above is option C. A group of students is asking people whether they use plastic bags. By doing such, the students are collecting data. They are collecting data of how many people uses plastic bags. Hope this answers the question.

6 0

4 years ago

Read 2 more answers

Nuclei of uranium atoms split apart is___?

Lynna [10]

Nuclei of uranium atoms split apart is . . . . known as nuclear fission

4 0

3 years ago

A pair of in-phase stereo speakers is placed side by side, 0.764 m apart. You stand directly in front of one of the speakers, 2.

Goryan [66]

Answer:

f = 2858.33 Hz

Explanation:

given,

distance between speaker (A) and the person = 2.34 m

Distance between speaker (B) and the person is AB =

= $\sqrt{(0.764)^2 + (2.34)^2}$

= 2.46 m

path difference d = BP - AP

= 2.46 - 2.34 m

= 0.12 m

now, λ = 0.12

speed of sound = 343 m/s

$f= \dfrac{c}{\lambda}$

$f= \dfrac{343}{0.12}$

f = 2858.33 Hz

the lowest frequency that will produce constructive interference is equal to

f = 2858.33 Hz

7 0

3 years ago

A 1.31 kg object is attached to a horizontal spring of force constant 2.70 N/cm and is started oscillating by pulling it 6.20 cm

goldfiish [28.3K]

Answer:

The answer is below

Explanation:

a) The change in energy is the difference between the final energy and the initial energy.

ΔE (energy change) = Ef (final energy) - Ei (initial energy)

$\Delta E=\frac{1}{2}kA_f^2 -\frac{1}{2}kA_i^2\\\\k=force\ constant=2.7\ N/cm=270\ N/m, A_f=final\ dispalacment= 3.7\ cm=0.037\ m,\\ A_i=initial \ displacement = 6.2\ cm=0.062\ m\\\\Hence:\\\\\Delta E=\frac{1}{2}(270)(0.037)^2 -\frac{1}{2}(270)(0.062)^2\\\\\Delta E=-0.334 \ J$

The negative sign shows that energy is lost to the environment. Hence 0.334 J is lost to the environment.

b) According to the law of conservation of energy, energy cannot be created or destroyed but transformed from one form to another.

The oscillating object loses energy due to wind resistance, friction between the spring and the object. Given that the air is frictionless, hence the energy loss is due to friction which is converted to heat.

6 0

3 years ago