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Makovka662 [10]

3 years ago

8

What's the difference between electromagnetic waves and electromagnetic spectrum?

1 answer:

White raven [17]3 years ago

4 0

The difference between the two is, well for one

Spectrum: The entire range that the "<em>waves" </em>could be such, as visible light, x-ray's and so on.

Waves: These are different because they aren't telling you or showing the entire spectrum just which they length that they are.

<em>It may confuse you but it makes sense to me (Sorry)</em>

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A 7 kg object attached to a horizontal string moves with constant speed in a circle on a frictionless horizontal surface. The ki

Marizza181 [45]

Answer:

Explanation:

Given

mass of object $m=7 kg$

kinetic Energy $k=36\ J$

Tension in string $T=326\ N$

mass is moving in a horizontal circle so tension is providing the centripetal acceleration

therefore $T=\frac{mv^2}{r}----1$

where r=radius of circle

kinetic energy of particle $k=\frac{1}{2}mv^2----2$

divide 1 and 2 we get

$\frac{T}{k}=\frac{\frac{mv^2}{r}}{\frac{1}{2}mv^2}$

$\frac{T}{k}=\frac{2}{r}$

$r=\frac{2k}{T}=\frac{2\times 36}{326}$

$r=0.2208\ m$

8 0

3 years ago

At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) (A) 0.39

exis [7]

Explanation:

It is given that,

Relativistic Mass of the stone, m₀ = 0.6

Mass, $m=0.76\ kg$

Relativistic mass is given by :

$m=\dfrac{m_o}{\sqrt{1-\dfrac{v^2}{c^2}}}$ .........(1)

Where

c is the speed of light

On rearranging equation (1) we get :

$v^2=c^2(1-(\dfrac{m_o}{m})^2)$

$v=c\sqrt{ (1-(\dfrac{m_o}{m})^2)}$

$v=c\sqrt{ (1-(\dfrac{0.6}{0.76})^2)}$

v = 0.61378 c

or

v = 0.6138 c

So, the correct option is (c). Hence, this is the required solution.

8 0

3 years ago

Three-Dimensional Thinking

gavmur [86]

Answer:

A.

Explanation: both triple by 3

4 0

3 years ago

Mt. Everest is 29,028 feet high. How many miles is this?

Viefleur [7K]

Mount. everest is 5.499 miles

6 0

3 years ago

Read 2 more answers

A horse travels 80 meters south in 20 seconds. What is its average velocity?

AURORKA [14]

Average velocity is a vector unit (i.e. includes magnitude <em>and </em>direction) calculated by working out distance ÷ time:

80 metres ÷ 20 seconds = 4 metres/seconds (m/s)

Therefore, your final answer is C. 4 m/s south.

7 0

3 years ago