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Makovka662 [10]
3 years ago
8

What's the difference between electromagnetic waves and electromagnetic spectrum?

Physics
1 answer:
White raven [17]3 years ago
4 0
The difference between the two is, well for one

Spectrum: The entire range that the "<em>waves" </em>could be such, as visible light, x-ray's and so on.

Waves: These are different because they aren't telling you or showing the entire spectrum just which they length that they are.

<em>It may confuse you but it makes sense to me (Sorry)</em>
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What is the volume of a 72 g of copper if copper has a density of 9 g/cm3
azamat

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8 centimetre cube

Explanation:

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Why do you think the temperature does not change much during a phase change?
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It depends on where the temperature is dropping, in which body so to speak. Generally, the temperature adapts to the two bodies, for example if a hot piece of metal meets a cold one, the two will continue until they are at an equal temperature, an intermediate temperature.

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The two major parts of the optical telescope
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The "objective" (lens or mirror) is the major major major part of
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2 years ago
1. How would you describe the area in which you live? Use terms such as desert, prairie, or
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3 years ago
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One electron collides elastically with a second electron initially at rest. After the collision, the radii of their trajectories
morpeh [17]

Answer:

63.750KeV

Explanation:

We are given that

Initial velocity of second electron,u_2=0

Radius,r_1=0

r_2=2.3 cm=\frac{2.3}{100}=0.023 m

1 m=100 cm

Magnetic field,B=0.0370 T

We have to determine the energy of the incident electron.

Mass of electron,m=9.1\times 10^{-31} kg

Charge on an electron,q=-1.6\times 10^{-19} C

Velocity,v=\frac{Bqr}{m}

Using the formula

Speed of electron,v_1=\frac{Bqr_1}{m}=\frac{0.0370\times 1.6\times 10^{-19}\times 0}{9.1\times 10^{-31}}=0

Speed of second electron,v_2=\frac{0.0370\times 1.6\times 10^{-19}\times 0.023}{9.1\times 10^{-31}}

v_2=1.5\times 10^8 m/s

Kinetic energy of incident electron=\frac{1}{2}mv^2_1+\frac{1}{2}mv^2_2

Kinetic energy of incident electron=0+\frac{1}{2}(9.1\times 10^{-31})(1.5\times 10^8)^2=1.02\times 10^{-14} J

Kinetic energy of incident electron=\frac{1.02\times 10^{-14}}{1.6\times 10^{-19}}=63750eV=\frac{63750}{1000}=63.750KeV

1KeV=1000eV

3 0
3 years ago
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