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3 years ago

How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid solution?

1 answer:

4 0

Work in amount of pure acid let x = gallons of pure acid required.
then we have the equation:-

x + 55(0.6) = 0.80(x + 55)

x + 33 = 0.80x + 44
0.20x = 11
x = 11/0.2 = 55 gallons answer

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Answer:

The height of the roof in his house is 72.43 ft.

Step-by-step explanation:

The volume of square pyramid is :

$V=\frac13 Bh$

B= area of the base.

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Given that,

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The side length of the base of the roof is 28 feet.

Since the base of the roof is square in shape.

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The area of the base is =(28×28) square feet

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Assume the height of the roof be h ft.

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According to the problem,

$\frac13 \times 784 \times h= 18929.3333$

$\Rightarrow h=\frac{18929.3333\times 3}{28}$

$\Rightarrow h\approx 72.43$ ft.

The height of the roof in his roof is 72.43 ft.

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3 years ago

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makkiz [27]

Answer:

Step-by-step explanation:

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4 years ago

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marishachu [46]

Answer:

x= 13

Step-by-step explanation:

−4/9(18x − 36) = −88

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3 years ago

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3 years ago

How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid​ solution?

How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid solution?