How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid solution?
1 answer:
Work in amount of pure acid let x = gallons of pure acid required.
then we have the equation:-
x + 55(0.6) = 0.80(x + 55)
x + 33 = 0.80x + 44
0.20x = 11
x = 11/0.2 = 55 gallons answer
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