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3 years ago

How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid solution?

1 answer:

4 0

Work in amount of pure acid let x = gallons of pure acid required.
then we have the equation:-

x + 55(0.6) = 0.80(x + 55)

x + 33 = 0.80x + 44
0.20x = 11
x = 11/0.2 = 55 gallons answer

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3 years ago

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Step-by-step explanation:

The given figure is a composite figure consisting of a rectangle AINE and a triangle AIL

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3 years ago

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3 years ago

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The most appropriate choice for square root will be given by-

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To learn more about square root of a number, refer to the link:

brainly.com/question/3617398

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1 year ago

How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid​ solution?

How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid solution?