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nadezda [96]
3 years ago
7

A soccer player has a limit of 700 calories in a sandwich and chips meal. The sandwich is 464 calories and each chip is 7 calori

es each. How many chips can he have? use c for to represent number of chips)
Mathematics
2 answers:
Blababa [14]3 years ago
8 0

Answer:

33 chips

Step-by-step explanation:

c= (700 - 464) ÷ 7 = 33

She can use 33 chips or less. I less cause she shouldn't eat too much calories.  

kkurt [141]3 years ago
5 0

Answer:

If you are asking for the equation, then 464+7c is less than or equal to 700 if you want the answer to the equation, then 33 chips

Step-by-step explanation:

464+7(33) is less than or equal to 700

464+231=695

695 is less than 700

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Kamila [148]

Answer:

Ratios to roses to lilies....6:9

Reduced.....2:3

Step-by-step explanation:

Pretty simple doesn't need explaining

8 0
3 years ago
Subtract whole number estimate.then find the difference estimate 428,734 -175,842
diamong [38]

You are estimating each into whole numbers. They are already whole numbers, and so just subtract.

428,734 - 175,842 = 252892

252,892 is your answer

hope this helps

3 0
3 years ago
A student writes an incorrect step while checking if the sum of the measures of the two remote interior angles of triangle ABC b
rosijanka [135]

Answer:

4.) Step 2; it should be m∠o + m∠p = 180 degrees (supplementary angles)

Step-by-step explanation:

o and p are supplementary angles, and therefore add up to 180 degrees.

5 0
3 years ago
This is Matrix for pre calc
gavmur [86]

The given system of equations in augmented matrix form is

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]

If you need to solve this, first get the matrix in RREF:

  • Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]

  • Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]

  • Add 164(row 3) to -91(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]

  • Multiply row 4 by 1/13080:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]

  • Add -153(row 4) to row 3:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]

  • Multiply row 3 by -1/91:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add 6(row 3) and -8(row 4) to row 2:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 2 by 1/5:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 1 by 1/3:

\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

So the solution to this system is (w,x,y,z)=(1,-2,4,-3).

6 0
3 years ago
find a parametric representation of the solution set of the linear equation. (enter your answer as a comma-separated list of equ
Ostrovityanka [42]

To represent the solution set of a linear equation parametrically, we introduce other parameters like s and t for the free variables.

Every linear equation has n - 1 free variables where n is the number of variables.

For x + y + z = 2, we have 3 variables and 3 - 1 = 2 free variables.

First, let y and z be the free variables, we first solve the linear equation for x to get:

x = 2 - y - z

Therefore , the parametric representation of the solution set is given by :

x = 2 - s -t

y = s

z = t

Learn more about The linear Equation at:

brainly.com/question/17748588

#SPJ4

5 0
2 years ago
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