Question

Find the 5th term of the geometric progression of the following values 1,2,4 and 8​

Answer 1

Answer:

16

Step-by-step explanation:

formula(T=ar^(n-1)) where common ratio(r)=2/1=2. first term(a)=1,n is the no. of tems and in this case n=5

Answer 2

Answer:

Hello,

16

Step-by-step explanation:

$2^{0} = 1$

$2^{1} = 2$

$2^{2} = 4$

$2^{3} = 8$

$2^{4} = 16$

2 x 1 = 2

2 x 2 = 4

2 x 4 = 8

2 x 8 = 16

2/1 = 4/2 = 8/4 = 16/8 = 2