Consider, 
. Let's say 
then the problem reduces to 
. (Do you understand this step?)
So then replacing a again with our definition we get,
.
So then replacing a again with our definition we get,
What the answer is pleaseeee
1 answer:
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Answer:
1. The margin of error is of 66.96 square feet.
2. The 95% confidence interval estimate for the population mean using the Student's t-distribution is between 1433.04 square feet and 1566.96 square feet
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 22 - 1 = 21
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.08
The margin of error is:
In which s is the standard deviation of the sample.
The margin of error is of 66.96 square feet.
The lower end of the interval is the sample mean subtracted by M. So it is 1500 - 66.96 = 1433.04 square feet
The upper end of the interval is the sample mean added to M. So it is 1500 + 314 = 1566.96 square feet
The 95% confidence interval estimate for the population mean using the Student's t-distribution is between 1433.04 square feet and 1566.96 square feet