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Lady_Fox [76]
3 years ago
10

A single unit of heredity that contains the information for an individual protein is referred to as a

Biology
1 answer:
Colt1911 [192]3 years ago
3 0
I dont even know the answer need points to ask my question


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Name the process responsible for the formation of glomerular filtrate<br>​
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Answer: Please refer to:

The process by which glomerular filtration occurs is called renal ultrafiltration. The force of hydrostatic pressure in the glomerulus (the force of pressure exerted from the pressure of the blood vessel itself) is the driving force that pushes filtrate out of the capillaries and into the slits in the nephron.

Explanation:

Not sure but hope it helps.

4 0
2 years ago
In a dihybrid cross with genotypes JjQq and JJQq, what is the probability of getting an offspring with genotype JjQq?
valentina_108 [34]
There is a 1:4 chance of getting JjQq. The parent JjQq can produce four genotypes: JQ, Jq, jQ, and jq. the parent JJQq can produce two genotypes: JQ and Jq. When we do a punnett square: 
JJQQ, JJQq, JjQQ, JjQq, 
JJQq, JJqq, JjQq, and Jjqq
There are two JjQq. 
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6 0
3 years ago
What kinds of action could a government take during a pandemic?
Cloud [144]

Answer:

During any pandemic, government can make people aware about that pandemic and can provide the necessary things like shelter, food etc. to poor people. Government can also help people by money.

4 0
2 years ago
Will anyone help me?
Anastasy [175]
The high heat capacity of water prevents fish body temperatures from changing during the winter.
5 0
3 years ago
What is the magnitude of the force exerted by the biceps fbiceps? What is the magnitude of the force exerted by the elbow felbow
Slav-nsk [51]

Answer:

<u> </u><u>The magnitude of the force exerted by the biceps </u>f_b_i_c_e_p_s<u> is 218.38N</u>

<u>The magnitude of the force exerted by the elbow </u>f_e_l_b_o_w<u> is 194.37N</u>

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps f_b_i_c_e_p_s -

Mass of the forearm=

m_f=1.50kg

Mass of the ball =

m_b_a_l_l=950g

   = 0.950kg

so, weight of the forearm=

w_f=m_f g

weight of the ball=

w_b_a_l_l=m_b_a_l_l g

Now , balancing torque about the elbow , we have-

F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36

F_b_i_c_e_p_s=218.38N

Now, lets calculate the force exerted by elbow F_e_l_b_o_w -

Balancing the vertical forces

F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l

F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)

F_e_l_b_o_w=194.37N

8 0
2 years ago
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