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Alecsey [184]
3 years ago
9

Daid1784 pls help (again)

Mathematics
2 answers:
Eva8 [605]3 years ago
6 0
56.29 is your answer i am 100% sure of it! plz mark brainlyest!!! have a great day:)
Usimov [2.4K]3 years ago
3 0

Answer:

1) C

2)A

3)B

4)D

5)C (I BET 100%)

Step-by-step explanation:

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What is the mean, median, and mode of 3,8,13,4,9,15,7,8,5,
Stella [2.4K]

Answer:

Mean:  8

Median:  8

Mode:  8

Step-by-step explanation:

Find the average

Mean: 3 + 4 + 5 + 7 + 8 + 8 + 9 + 13 + 15 = 72

Divide by the amount on numbers:  72 / 9 = 8

8 is the average

Find the middle

Median:  3, 4, 5, 7, 8, 8, 9, 13, 15

8 is the middle

Find the most common

Mode:  3, 4, 5, 7, 8, 8, 9, 13, 15

8 is most common

3 0
3 years ago
Read 2 more answers
ASAP PLEASE HELP!!!!!! Find the y-intercept of the rational function. A rational function is graphed in the first quadrant, and
nikdorinn [45]

Answer:

(0,-2)

Step-by-step explanation:

The y-intercept is simply when the function touches or crosses the y-axis.

We're told that the graph crosses the y-axis at -2. In other words, the y-intercept is at -2.

The ordered pair would be (0,-2)

7 0
4 years ago
En una fiesta se desea elegir un grupo de 3 personas de entre 6 matrimonios, si dos miembros de la misma pareja no pueden ser el
LenaWriter [7]

Answer:

Hay 160 maneras

Step-by-step explanation:

Para calcular de cuántas maneras se puede seleccionar x elementos de un grupo de n elementos podemos usar la siguiente fórmula:

nCx=\frac{n!}{x!(n-x)!}

Si vas a elegir 3 personas de entre 6 matrimonios y dos miembros de la misma pareja no pueden ser elegidos, entonces podemos decir que se está eligiendo 3 matrimonios y en cada matrimonio se está eligiendo un representante.

Entonces, podemos calcular de cuántas maneras se puede escoger 3 matrimonios de los 6, así:

6C3=\frac{6!}{3!(6-3)!}=20

Adicionalmente, para cada uno de los 3 matrimonios hay 2 opciones para ser representantes. Esto significa que hay 2^3 maneras de escoger representantes en cada una de las 20 formas calculadas anteriormente.

Por lo tanto se puede formar el grupo de 3 personas de 160 maneras diferentes:

20*2^3=160

6 0
3 years ago
Is. 36yd2ft bigger than 114ft 2in
Zarrin [17]
NO! 
1 yd=3 ft
36*3=108
108+2=110
114>110, therefore no
5 0
4 years ago
How can you use the multiplication property of equality to rewrite the equation 0.6x+4.8=7.2 so that the numbers in the problem
Mars2501 [29]

We are given the equation:

0.6 x + 4.8 = 7.2

 

In this case, the multiplication property of equality states that whatever is multiplied on one side should also be multiplied on the other side. Now we need to find the number that will make everything a whole number, in this case 5. Multiply everything by 5:

5 * (0.6 x + 4.8 = 7.2)

3 x + 24 = 36

However we can see that we can still further simplify the equation by multiplying everything by 1/3:

(1/3) * (3 x + 24 = 36)

x + 8 = 12

or

x = 4

6 0
3 years ago
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