Which event was most influential in turning American public opinion against Germany?

A cross section is made parallel to the bases of a right triangular prism. Which of the following statements is true regarding t

user100 [1]

Answer:

The area of the cross section is equal to the area of the base.

Step-by-step explanation:

4 0

3 years ago

The Institute of Management Accountants (IMA) conducted a survey of senior finance professionals to gauge members’ thoughts on g

DochEvi [55]

Answer:

(1) The probability that the sample percentage indicating global warming is having a significant impact on the environment will be between 64% and 69% is 0.3674.

(2) The two population percentages that will contain the sample percentage with probability 90% are 0.57 and 0.73.

(3) The two population percentages that will contain the sample percentage with probability 95% are 0.55 and 0.75.

Step-by-step explanation:

Let X = number of senior professionals who thought that global warming is having a significant impact on the environment.

The random variable X follows a Binomial distribution with parameters n = 100 and p = 0.65.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of p if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

Check the conditions as follows:

$np= 100\times 0.65=65>10\\n(1-p)=100\times (1-0.65)=35>10$

Thus, a Normal approximation to binomial can be applied.

So, $\hat p\sim N(p, \frac{p(1-p)}{n})=N(0.65, 0.002275)$ .

(1)

Compute the value of $P(0.64$ as follows:

$P(0.64$

$=P(-0.20$

Thus, the probability that the sample percentage indicating global warming is having a significant impact on the environment will be between 64% and 69% is 0.3674.

(2)

Let $p_{1}$ and $p_{2}$ be the two population percentages that will contain the sample percentage with probability 90%.

That is,

$P(p_{1}$

Then,

$P(p_{1}$

$P(\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}$

$P(-z$

The value of z for P (Z < z) = 0.95 is

z = 1.65.

Compute the value of $p_{1}$ and $p_{2}$ as follows:

$-z=\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}\\-1.65=\frac{p_{1}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{1}=0.65-(1.65\times 0.05)\\p_{1}=0.5675\\p_{1}\approx0.57$ $z=\frac{p_{2}-p}{\sqrt{\frac{p(1-p)}{n}}}\\1.65=\frac{p_{2}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{2}=0.65+(1.65\times 0.05)\\p_{1}=0.7325\\p_{1}\approx0.73$

Thus, the two population percentages that will contain the sample percentage with probability 90% are 0.57 and 0.73.

(3)

Let $p_{1}$ and $p_{2}$ be the two population percentages that will contain the sample percentage with probability 95%.

That is,

$P(p_{1}$

Then,

$P(p_{1}$

$P(\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}$

$P(-z$

The value of z for P (Z < z) = 0.975 is

z = 1.96.

Compute the value of $p_{1}$ and $p_{2}$ as follows:

$-z=\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}\\-1.96=\frac{p_{1}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{1}=0.65-(1.96\times 0.05)\\p_{1}=0.552\\p_{1}\approx0.55$ $z=\frac{p_{2}-p}{\sqrt{\frac{p(1-p)}{n}}}\\1.96=\frac{p_{2}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{2}=0.65+(1.96\times 0.05)\\p_{1}=0.748\\p_{1}\approx0.75$

Thus, the two population percentages that will contain the sample percentage with probability 95% are 0.55 and 0.75.

7 0

4 years ago

(-3x4y5)(8xy5)(-6x3y

tresset_1 [31]

Answer:

5

Step-by-step explanation:

I think its 5 I don't know for sure.

7 0

3 years ago

PLZZZ I NEED THIS QUICK What is [-4.6].

andreyandreev [35.5K]

Answer:

Slope=0

Step-by-step explanation:

I don't know what you need done but I will try my best.

3 0

4 years ago

time it takes to fly from City A to City B a. Is the distance a baseball travels in the air after being hit a discrete random v

Tresset [83]

Complete question is;

Determine whether the random variable is discrete or continuous.

a. The time it takes to fly from City Upper A to City Upper B.

b. The time it takes for a light bulb to burn out.

c. The number of fish caught during a fishing tournament.

d. The number of textbook authors now sitting at a computer.

e. The distance a baseball travels in the air after being hit.

a. Is the time it takes to fly from City Upper A to City Upper B discrete or continuous? A. The random variable is discrete. B. The random variable is continuous.

Answer:

a) continuous random variable.

b) continuous random variable

c) discrete random variable

d) discrete random variable

e) continuous random variable

Step-by-step explanation:

A discrete variable is one where the value of the variable is gotten by counting the variables.

Meanwhile, a continuous variable is one where the value of the variable is gotten by measuring the variables.

For options a & b, the time taken is the variable that is measured. Thus, they are both continuous random variable.

Also, for option e, the distance traveled is the measured variable and thus it is also a continuous random variable.

In option c, the number of fishes can be counted. Also, for option d, the number of textbook authors can be counted. Thus, the values of the variables can be gotten by counting. . Therefore, they are both discrete random variable.

7 0

4 years ago