Lightly draw a vertical line at -3 (x= -3 is the divider) on the left side graph x + 1, on the right side graph 1/2x + 2.
because these equations don't match up at the -3 coordinate, you have to draw an open (not colored in) circle at the beginning at the 1/2x-2 equation
Answer:
<u>Third Option</u>: 
Step-by-step explanation:
Given the points on the graph, (4, 5) and (-4, -5):
In order to determine the equation of the given graph in slope-intercept form, y = mx + b:
Use the given points to solve for the slope:
Let (x₁, y₁) = (-4, -5)
(x₂, y₂) = (4, 5)
m = (y₂ - y₁)/(x₂ - x₁)

Therefore, the slope of the line is:
.
Next, use one of the given points on the graph, (4, 5) to solve for the y-intercept, b:
y = mx + b
5 =
+ b
5 = 5 + b
5 - 5 = 5 - 5 + b
0 = b
Therefore, the linear equation in slope-intercept form is:
. The correct answer is Option 3.
Answer:
Step-by-step explanation:
1) m∠1 +m∠2 + m∠3 = m∠LAM (Angle addition postulate)
2) m∠1 + m∠2 + m∠3 = 180 (def. of straight angle)
3) y║z (Given)
4) ∠1 ≅ ∠5 (alternate interior angles theorem)
5) ∠3 ≅ ∠6 (alternate interior angles theorem)
6) Since m∠1 + m∠2 + m∠3 = 180
m∠5 + m∠2 + m∠6 = 180
Hence proved.
The answer is 5x + 10 because you have to times 5 by everything in the parenteses