Answer:
Acid + Oxide or Hydroxide
Many oxide, hydroxide and carbonate compounds
are insoluble in water, but do react with acid.
Acid + Oxide → Salt + Water
Acid + Hydroxide → Salt + Water
MgO (s) + HNO3 (aq) → Mg(NO3)2 (aq) + H2O (l)
CuOH (s) + HCl (aq) → CuCl (aq) + H2O (l)
Explanation:
lead compounds are the oxides: lead monoxide, PbO, in which lead is in the +2 state; lead dioxide, PbO2, in which lead is in the +4 state; and trilead tetroxide, Pb3O4. Lead monoxide exists in two modifications, litharge and massicot. Litharge, or alpha lead monoxide, is a red or reddish…
Answer:
Explanation:
According to the law of definite proportions, particles in a compound combine by a defined stoichiometric ratio. This ratio is also calculated in terms of moles.
In order to find the ratio between the particles in a compound, we need to find the molar ratio of each species.
Notice that the ratio between the number of moles of zinc to the number of moles of nitrogen is:
This means if we are given 1 zinc ion, we expect to have a total of 2 nitrogen atoms. Therefore, x = 2.
Answer:
Sweets are sold loose, or pre-packed in 120g bags.
The 120 g bags are £1.49 each.
The loose sweets are £0.89 for 100g.
By calculating the price per gram, determine which is better value. Show your working.
<span>Copper sulfate, CuSO4 ===> (Cu^2+) (SO4^2-). </span>
<span>That means copper ions have a positive charge in the solution of this compound and are therefore attracted to the negative electrode, cathode. Just wanted to clear that out because "it accepts electrons there" is an invalid and ambiguous answer. </span>
<span>Good luck.</span>
Answer:
pH = 10.505
Explanation:
Molar mass of Amphetamine ( C9H13N) = 135 g/mol
Given that the concentration of Amphetamine = 225 mg/L
mass of Amphetamine in one Liter = = 0.225 g
Number of moles of Amphetamine in one liter =
= 0.001667 mol
∴ molarity = 0.0017 M
C₉H₁₃N + H₂O --------> C₉H₁₃NH⁺ + OH⁻
I(M) 0.001667 M 0 0
C(M) -x x x
E(M) 0.001667 - x x x
Pkb = -log Kb = 4.2
∴ Kb = 6.309 x 10⁻⁵
Kb = 6.309 x 10⁻⁵
Equilibrium constant = [C₉H₁₃NH⁺][OH⁻]/ [C₉H₁₃N]
6.309 x 10⁻⁵ = x² / 0.001667-x
where 0.001667 -x ≅ 0.001667
Then;
x² = 6.309 x 10⁻⁵ × 0.001667
x² = 1.0517103 × 10⁻⁷
x =
x = 0.00032 M
x = [OH-] = 0.00032 M
∴ pOH = -log [OH-]
pOH = -log (0.00032)
pOH =3.495
pH = 14 - 3.495
= 10.505